我知道这是一个奇怪的问题，我冒着露出绿色的风险，但我在这里撕扯我的头发。
我有一个按预期工作的C ++示例。这是令人讨厌的一点：
BIRDFRAME frame;
birdGetMostRecentFrame(GROUP_ID,&frame);
BIRDREADING *bird_data;
bird_time=frame.dwTime;
for(FBBloop=FBBstart; FBBloop<FBBend; FBBloop++ )
{
bird_data = &frame.reading[FBBloop];
// Do stuff
}
请注意，bird_data是一个指针，并被指定为frame.reading[FBBloop]的地址。我的应用程序是用C＃编写的，所以没有任何这个指针malarkey。相应的位看起来像这样：
FlockOfBirds.BIRDFRAME frame = new FlockOfBirds.BIRDFRAME();
FlockOfBirds.birdGetMostRecentFrame(1, ref frame);
Console.WriteLine("T:{0}",frame.dwTime.ToString());
FlockOfBirds.BIRDREADING reading;
for (int k = 1; k <= sysconf.byNumDevices; k++)
{
reading = frame.readings[k];
Console.WriteLine(" [{0}][{1}][{2}]", reading.position.nX.ToString(), reading.position.nY.ToString(), reading.position.nZ.ToString());
}
问题在于，在C＃示例中，只有reading[1]具有有意义的数据。在C ++示例中，bird_data[1]和bird_data[2]都有良好的数据。奇怪的是，reading[2-n]并非所有值都归零，但似乎是随机且不变的。以下是C＃app的输出结果：
T:17291325
[30708][-2584][-5220]
[-19660][1048][-31310]
T:17291334
[30464][-2588][-5600]
[-19660][1048][-31310]
T:17291346
[30228][-2600][-5952]
[-19660][1048][-31310]
T:17291354
[30120][-2520][-6264]
[-19660][1048][-31310]
T:17291363
[30072][-2388][-6600]
[-19660][1048][-31310]
请注意，每个条目的顶部三元组与之前和之后的条目略有不同。在C ++应用程序中，底线表现相似，但在此始终保持不变。
这可能与缺乏指向和解除引用有关吗？还是我完全吠叫错了树？我做过其他明显愚蠢的事吗？最重要的是：我如何让它发挥作用？
更新：Structs＆amp;实习医生
C ++
// Bird reading structure
typedef struct tagBIRDREADING
{
BIRDPOSITION position; // position of receiver
BIRDANGLES angles; // orientation of receiver, as angles
BIRDMATRIX matrix; // orientation of receiver, as matrix
BIRDQUATERNION quaternion; // orientation of receiver, as quaternion
WORD wButtons; // button states
}
BIRDREADING;
// Bird frame structure
//
// NOTE: In stand-alone mode, the bird reading is stored in reading[0], and
// all other array elements are unused. In master/slave mode, the "reading"
// array is indexed by bird number - for example, bird #1 is at reading[1],
// bird #2 is at reading[2], etc., and reading[0] is unused.
typedef struct tagBIRDFRAME
{
DWORD dwTime; // time at which readings were taken, in msecs
BIRDREADING reading[BIRD_MAX_DEVICE_NUM + 1]; // reading from each bird
}
BIRDFRAME;
BOOL DLLEXPORT birdGetMostRecentFrame(int nGroupID, BIRDFRAME *pframe);
C＃：
[StructLayout(LayoutKind.Sequential, Pack = 0)]
public struct BIRDREADING
{
public BIRDPOSITION position;
public BIRDANGLES angles;
public BIRDMATRIX matrix;
public BIRDQUATERNION quaternion;
public ushort wButtons;
}
[StructLayout(LayoutKind.Sequential, Pack = 0)]
public struct BIRDFRAME
{
public uint dwTime;
[MarshalAs(UnmanagedType.ByValArray, SizeConst = 127)]
public BIRDREADING[] readings;
}
[DllImport(@"Bird.dll", CallingConvention = CallingConvention.Cdecl)]
public static extern bool birdGetMostRecentFrame(int nGroupID, ref BIRDFRAME frame);
**更新2：更多结构：**
C ++
#pragma pack(1) // pack the following structures on one-byte boundaries
// Bird position structure
typedef struct tagBIRDPOSITION
{
short nX; // x-coordinate
short nY; // y-coordinate
short nZ; // z-coordinate
}
BIRDPOSITION;
// Bird angles structure
typedef struct tagBIRDANGLES
{
short nAzimuth; // azimuth angle
short nElevation; // elevation angle
short nRoll; // roll angle
}
BIRDANGLES;
// Bird matrix structure
typedef struct tagBIRDMATRIX
{
short n[3][3]; // array of matrix elements
}
BIRDMATRIX;
// Bird quaternion structure
typedef struct tagBIRDQUATERNION
{
short nQ0; // q0
short nQ1; // q1
short nQ2; // q2
short nQ3; // q3
}
BIRDQUATERNION;
#pragma pack() // resume normal packing of structures
C＃
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public struct BIRDPOSITION
{
public short nX;
public short nY;
public short nZ;
}
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public struct BIRDANGLES
{
public short nAzimuth; // azimuth angle
public short nElevation; // elevation angle
public short nRoll; // roll angle
}
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public unsafe struct BIRDMATRIX
{
public fixed short n[9];
}
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public struct BIRDQUATERNION
{
public short nQ0; // q0
public short nQ1; // q1
public short nQ2; // q2
public short nQ3; // q3
}
答案 0 :(得分：1)
我在两个项目（C ++ / C＃）中尝试了你的结构，它似乎工作正常。
我在C ++中使用它：
#include "stdafx.h"
#include "windows.h"
#pragma pack(1) // pack the following structures on one-byte boundaries
// Bird position structure
typedef struct tagBIRDPOSITION
{
short nX; // x-coordinate
short nY; // y-coordinate
short nZ; // z-coordinate
}
BIRDPOSITION;
// Bird angles structure
typedef struct tagBIRDANGLES
{
short nAzimuth; // azimuth angle
short nElevation; // elevation angle
short nRoll; // roll angle
}
BIRDANGLES;
// Bird matrix structure
typedef struct tagBIRDMATRIX
{
short n[3][3]; // array of matrix elements
}
BIRDMATRIX;
// Bird quaternion structure
typedef struct tagBIRDQUATERNION
{
short nQ0; // q0
short nQ1; // q1
short nQ2; // q2
short nQ3; // q3
}
BIRDQUATERNION;
#pragma pack() // resume normal packing of structures
typedef struct tagBIRDREADING
{
BIRDPOSITION position; // position of receiver
BIRDANGLES angles; // orientation of receiver, as angles
BIRDMATRIX matrix; // orientation of receiver, as matrix
BIRDQUATERNION quaternion; // orientation of receiver, as quaternion
WORD wButtons; // button states
}
BIRDREADING;
#define BIRD_MAX_DEVICE_NUM 126
// Bird frame structure
//
// NOTE: In stand-alone mode, the bird reading is stored in reading[0], and
// all other array elements are unused. In master/slave mode, the "reading"
// array is indexed by bird number - for example, bird #1 is at reading[1],
// bird #2 is at reading[2], etc., and reading[0] is unused.
typedef struct tagBIRDFRAME
{
DWORD dwTime; // time at which readings were taken, in msecs
BIRDREADING reading[BIRD_MAX_DEVICE_NUM + 1]; // reading from each bird
}
BIRDFRAME;
extern "C" __declspec( dllexport ) BOOL birdGetMostRecentFrame(int nGroupID, BIRDFRAME *pframe) {
pframe->dwTime = GetTickCount();
for (int i = 0; i < sizeof(pframe->reading)/sizeof(*pframe->reading); i++) {
pframe->reading[i] = BIRDREADING();
pframe->reading[i].position.nX = (short)i;
pframe->reading[i].position.nY = (short)i + 1;
pframe->reading[i].position.nZ = (short)i + 2;
}
return TRUE;
}
这在C＃：
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public struct BIRDPOSITION
{
public short nX;
public short nY;
public short nZ;
}
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public struct BIRDANGLES
{
public short nAzimuth; // azimuth angle
public short nElevation; // elevation angle
public short nRoll; // roll angle
}
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public unsafe struct BIRDMATRIX
{
public fixed short n[9];
}
[StructLayout(LayoutKind.Sequential, Pack = 1)]
public struct BIRDQUATERNION
{
public short nQ0; // q0
public short nQ1; // q1
public short nQ2; // q2
public short nQ3; // q3
}
[StructLayout(LayoutKind.Sequential, Pack = 0)]
public struct BIRDREADING
{
public BIRDPOSITION position;
public BIRDANGLES angles;
public BIRDMATRIX matrix;
public BIRDQUATERNION quaternion;
public ushort wButtons;
}
[StructLayout(LayoutKind.Sequential, Pack = 0)]
public struct BIRDFRAME
{
public uint dwTime;
[MarshalAs(UnmanagedType.ByValArray, SizeConst = 127)]
public BIRDREADING[] readings;
}
public partial class Form1 : Form
{
[DllImport(@"Bird.dll", CallingConvention = CallingConvention.Cdecl)]
public static extern bool birdGetMostRecentFrame(int nGroupID, ref BIRDFRAME frame);
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
BIRDFRAME bf = new BIRDFRAME();
if (checkBox1.Checked)
{
bf.readings = new BIRDREADING[127];
}
if (birdGetMostRecentFrame(0, ref bf)) {
listBox1.Items.Add(bf.dwTime.ToString());
Console.WriteLine(bf.dwTime.ToString());
for (int k = 1; k <= 3; k++)
{
var reading = bf.readings[k];
Console.WriteLine(String.Format(" [{0}][{1}][{2}]", reading.position.nX.ToString(), reading.position.nY.ToString(), reading.position.nZ.ToString()));
listBox1.Items.Add(String.Format(" [{0}][{1}][{2}]", reading.position.nX.ToString(), reading.position.nY.ToString(), reading.position.nZ.ToString()));
}
}
}
}
在这两种情况下（读取在C＃中初始化为新的，否则它会返回有意义的数据：
40067905
[1][2][3]
[2][3][4]
[3][4][5]
40068653
[1][2][3]
[2][3][4]
[3][4][5]
40069418
[1][2][3]
[2][3][4]
[3][4][5]
40072585
[1][2][3]
[2][3][4]
[3][4][5]
在Windows7 64位上做了吗？ 我正在为VS2010添加两个项目的ZIP。
这是链接：
http://hotfile.com/dl/115296617/9644496/testCS.zip.html
您似乎在该位置struct：/
中设置了错误的值答案 1 :(得分：0)
似乎sysconf.byNumDevices == 1所以i <= sysconf.byNumDevices只循环一次而你正在读取未初始化的内存段。
尝试打印sysconf.byNumDevices，如果是1，请尝试跟踪该问题。
答案 2 :(得分：0)
.NET中的数组基于零，而不是基于数组。可能是吗？当然，.NET也有严格的边界检查，所以我原本期望你对数组的“最后”访问也会失败，也会出现异常。
无法访问FlockOfBirds来源，我不确定还能告诉您什么。
答案 3 :(得分：0)
只是一个想法：转到你的方法时你真的需要参考吗？
FlockOfBirds.BIRDFRAME frame = new FlockOfBirds.BIRDFRAME();
FlockOfBirds.birdGetMostRecentFrame(1, ref frame);
如果我没有弄错，那么在c＃中，无论如何都会通过引用传递所有类。我可能会生气，但你不是把裁判传给裁判？