Question

我想创建一个新变量，如果变量$ Who.went.first包含在变量$ Who.should.go.first中，则它将为新变量返回TRUE，否则返回FALSE。 $ Who.should.go.first和$ Who.went.first都具有与输入相同的汽车名称集，但出于某些原因，所有$ Who.should.go.first输入均具有文本“（Aspect）”最后，因此我希望该函数检查$ Who.went.first包含在$ Who.went.first中，而不是查找完全匹配的内容。

我正尝试使用ifelse函数和％in％进行此操作，如下所示。

Cooperation_2clean$correct.go.first <- ifelse((Cooperation_2clean$Who.went.first %in% Cooperation_2clean$Who.should.go.first), "TRUE", "FALSE")

它将创建一个新变量，除非每种情况都返回FALSE。例如，如果$ Who.went.first是“ AV_0_Blue”，而$ Who.should.go.first是“ AV_0_Blue（Aspect）”，则当它为true时将返回FALSE。

我应该使用诸如case_when之类的其他函数吗？

编辑：

一些示例数据：

Cooperation_2clean <- data.frame("Who.should.go.first" = c("AV_0_Blue (Aspect)", "Human_2_BlueCW (Aspect)", "AV_0_Blue (Aspect)", "AV_2_Green (Aspect)", "AV_3_Orange (Aspect)"), "Who.went.first" = c("AV_0_Blue", "AV_3_Orange", "AV_0_Blue", "AV_2_Green", "AV_2_Green"))

Answer 1

我认为grepl是您所追求的功能。例如

biggerstring <- 'LargeItemFindText'
smallstring <-  'geItem'
badstring <- 'notthere'

ifelse(grepl(smallstring, biggerstring) > 0, 1, 0)
ifelse(grepl(badstring, biggerstring) > 0, 1, 0)

编辑

在您的示例中，您将grepl与apply函数一起使用。工作代码：

Cooperation_2clean <- data.frame("Who.should.go.first" = c("AV_0_Blue (Aspect)", "Human_2_BlueCW (Aspect)", "AV_0_Blue (Aspect)", "AV_2_Green (Aspect)", "AV_3_Orange (Aspect)"), "Who.went.first" = c("AV_0_Blue", "AV_3_Orange", "AV_0_Blue", "AV_2_Green", "AV_2_Green"))

Cooperation_2clean$Output <- sapply(1:nrow(Cooperation_2clean), function(x) grepl(Cooperation_2clean$Who.went.first[x],
                                                     Cooperation_2clean$Who.should.go.first[x]))

我认为这是比特定字符串替换更通用的解决方案，因为它还捕获了可能的双倍空格，无间距，使用括号等。

Answer 2

这是我的解决方法

library("tidyverse")

# Your sample dataframe
Cooperation_2clean <-
  data.frame(
    "Who.should.go.first" = c(
      "AV_0_Blue (Aspect)",
      "Human_2_BlueCW (Aspect)",
      "AV_0_Blue (Aspect)",
      "AV_2_Green (Aspect)",
      "AV_3_Orange (Aspect)"
    ),
    "Who.went.first" = c(
      "AV_0_Blue",
      "AV_3_Orange",
      "AV_0_Blue",
      "AV_2_Green",
      "AV_2_Green"
    )
  )

# Create a new column named "new_var" where we check rowise
# if the string in Who.went.first is contained in Who.should.go.first
Cooperation_2clean %>% 
  rowwise() %>% 
  mutate(new_var = grepl(Who.went.first, Who.should.go.first))

# Who.should.go.first     Who.went.first new_var
#   <fct>                   <fct>          <lgl>  
# 1 AV_0_Blue (Aspect)      AV_0_Blue      TRUE   
# 2 Human_2_BlueCW (Aspect) AV_3_Orange    FALSE  
# 3 AV_0_Blue (Aspect)      AV_0_Blue      TRUE   
# 4 AV_2_Green (Aspect)     AV_2_Green     TRUE   
# 5 AV_3_Orange (Aspect)    AV_2_Green     FALSE

Answer 3

有一个名为stringr的软件包可以用来做这种事情。

# Your sample dataframe
Cooperation_2clean <-
  data.frame(
    "Who.should.go.first" = c(
      "AV_0_Blue (Aspect)",
      "Human_2_BlueCW (Aspect)",
      "AV_0_Blue (Aspect)",
      "AV_2_Green (Aspect)",
      "AV_3_Orange (Aspect)"
    ),
    "Who.went.first" = c(
      "AV_0_Blue",
      "AV_3_Orange",
      "AV_0_Blue",
      "AV_2_Green",
      "AV_2_Green"
    ),
    stringsAsFactors = FALSE
  )

library(stringr)
new_var <- str_detect(Cooperation_2clean$Who.should.go.first,Cooperation_2clean$Who.went.first)
# [1]  TRUE FALSE  TRUE  TRUE FALSE

library(stringr)
library(dplyr)
Cooperation_2clean <- Cooperation_2clean %>%
  mutate(new_var = str_detect(Who.should.go.first,Who.went.first))
#       Who.should.go.first Who.went.first new_var
# 1      AV_0_Blue (Aspect)      AV_0_Blue    TRUE
# 2 Human_2_BlueCW (Aspect)    AV_3_Orange   FALSE
# 3      AV_0_Blue (Aspect)      AV_0_Blue    TRUE
# 4     AV_2_Green (Aspect)     AV_2_Green    TRUE
# 5    AV_3_Orange (Aspect)     AV_2_Green   FALSE

使用ifelse和％in％在r中创建新变量

3 个答案: