Question

我正在尝试根据同一字典的值为字典的每个键生成语法。下面是我的代码：

my_dict={'key1':('a','b','c','d'), 'key2':('e','f','c','h'}
global_syntax=""
for key, val in my_dict.iteritems():
    if val[2][0]='c':
        mysyntax(key)

def write_to_file (syntax_to_write):
    global global_syntax
    global_syntax=global_syntax+str(syntax_to_write)

def mysyntax(key):
    my_variable=key
    my_syntax="""
do all stuff + {key} + {val}
""".format(\
key=key,\
val=val[2][0])
    write_to_file(mysyntax.encode('utf8'))

所以在这里，在生成的文件中，我想要：

执行所有任务键1 c

做所有东西key2 c

但是当我运行它时，这告诉我未定义mysyntax。因为我从字典中读取数据，所以我们有什么特殊性吗？

Answer 1

# define your function before you are calling it
def mysyntax(key):
    my_variable=key
    my_syntax="\"" # to use  quotation marks inside quotation marks use "\"" instead of """

my_dict={'key1':('a','b','c','d'), 'key2':('e','f','c','h')}
global_syntax=""
for key, val in my_dict.items():
    if val[2][0]=='c': # to Equality Check Difference use == instead of =
        mysyntax(key)

如何为字典的每个键生成语法？

1 个答案: