2WD蓝牙控制汽车无法停止的问题

时间:2019-06-26 07:39:11

标签: c++ arduino

因此,我正在为2WD蓝牙控制的足球车创建代码。当我向前按时,它会不停地向前移动。

我尝试过几次更改代码,例如:

if( val == '1') // Forward
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(1);
      digitalWrite(m1a, LOW);
      digitalWrite(m2a, LOW);
    }

收件人:

if( val == '1') // Forward
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2b, LOW);
    }

此处显示完整代码:

// Starting of Program
#include <SoftwareSerial.h>

SoftwareSerial mySerial(10,11);
int m1a = A3;
int m1b = A4;
int m2a = 3;
int m2b = A5;
char val;

void setup() 
{  
pinMode(m1a, OUTPUT);  // Digital pin 10 set as output Pin
pinMode(m1b, OUTPUT);  // Digital pin 11 set as output Pin
pinMode(m2a, OUTPUT);  // Digital pin 12 set as output Pin
pinMode(m2b, OUTPUT);  // Digital pin 13 set as output Pin
mySerial.begin(9600);
}

void loop()
{
  while (mySerial.available() > 0)
  {
  val = mySerial.read();
  mySerial.println(val);
  }

  if( val == '1') // Forward
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(1);
      digitalWrite(m1a, LOW);
      digitalWrite(m2a, LOW);
    }
  else if(val == '2') // Backward
    {
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, HIGH);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, HIGH); 
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
    }

    else if(val == '3') //Left
    {
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, HIGH);
      digitalWrite(m2a, HIGH);
      digitalWrite(m2b, LOW);
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
    }
    else if(val == '4') //Right
    {
      digitalWrite(m1a, HIGH);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, HIGH); 
      delay(200);
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
    }

    else if(val == 'S')
    {
      digitalWrite(m1a, LOW);
      digitalWrite(m1b, LOW);
      digitalWrite(m2a, LOW);
      digitalWrite(m2b, LOW); 
      delay(1000);
      digitalWrite(m2a, HIGH);
    }
}

// End of program

没有错误的按摩请帮助。 我在手机上使用this app,最后11行代码是(val =='S'),用于表示应用程序中的停止按钮。

我只需要在按下按钮时移动它,而在没有按下任何按钮时停止它。不需要停止按钮。

1 个答案:

答案 0 :(得分:1)

if( val == '1') // Forward
{
  digitalWrite(m1a, HIGH);
  digitalWrite(m1b, LOW);
  digitalWrite(m2a, HIGH);
  digitalWrite(m2b, LOW);
  delay(1);
  digitalWrite(m1a, LOW);
  digitalWrite(m2a, LOW);
}

收件人

if( val == '1') // Forward
{
  digitalWrite(m1a, HIGH);
  digitalWrite(m1b, LOW);
  digitalWrite(m2a, HIGH);
  digitalWrite(m2b, LOW);
  delay(1);
  digitalWrite(m1a, LOW);
  digitalWrite(m2a, LOW);
  val = ' ';

}