因此,我正在为2WD蓝牙控制的足球车创建代码。当我向前按时,它会不停地向前移动。
我尝试过几次更改代码,例如:
if( val == '1') // Forward
{
digitalWrite(m1a, HIGH);
digitalWrite(m1b, LOW);
digitalWrite(m2a, HIGH);
digitalWrite(m2b, LOW);
delay(1);
digitalWrite(m1a, LOW);
digitalWrite(m2a, LOW);
}
收件人:
if( val == '1') // Forward
{
digitalWrite(m1a, HIGH);
digitalWrite(m1b, LOW);
digitalWrite(m2a, HIGH);
digitalWrite(m2b, LOW);
delay(200);
digitalWrite(m1a, LOW);
digitalWrite(m2a, LOW);
digitalWrite(m1b, LOW);
digitalWrite(m2b, LOW);
}
此处显示完整代码:
// Starting of Program
#include <SoftwareSerial.h>
SoftwareSerial mySerial(10,11);
int m1a = A3;
int m1b = A4;
int m2a = 3;
int m2b = A5;
char val;
void setup()
{
pinMode(m1a, OUTPUT); // Digital pin 10 set as output Pin
pinMode(m1b, OUTPUT); // Digital pin 11 set as output Pin
pinMode(m2a, OUTPUT); // Digital pin 12 set as output Pin
pinMode(m2b, OUTPUT); // Digital pin 13 set as output Pin
mySerial.begin(9600);
}
void loop()
{
while (mySerial.available() > 0)
{
val = mySerial.read();
mySerial.println(val);
}
if( val == '1') // Forward
{
digitalWrite(m1a, HIGH);
digitalWrite(m1b, LOW);
digitalWrite(m2a, HIGH);
digitalWrite(m2b, LOW);
delay(1);
digitalWrite(m1a, LOW);
digitalWrite(m2a, LOW);
}
else if(val == '2') // Backward
{
digitalWrite(m1a, LOW);
digitalWrite(m1b, HIGH);
digitalWrite(m2a, LOW);
digitalWrite(m2b, HIGH);
delay(200);
digitalWrite(m1a, LOW);
digitalWrite(m1b, LOW);
digitalWrite(m2a, LOW);
digitalWrite(m2b, LOW);
}
else if(val == '3') //Left
{
digitalWrite(m1a, LOW);
digitalWrite(m1b, HIGH);
digitalWrite(m2a, HIGH);
digitalWrite(m2b, LOW);
delay(200);
digitalWrite(m1a, LOW);
digitalWrite(m1b, LOW);
digitalWrite(m2a, LOW);
digitalWrite(m2b, LOW);
}
else if(val == '4') //Right
{
digitalWrite(m1a, HIGH);
digitalWrite(m1b, LOW);
digitalWrite(m2a, LOW);
digitalWrite(m2b, HIGH);
delay(200);
digitalWrite(m1a, LOW);
digitalWrite(m1b, LOW);
digitalWrite(m2a, LOW);
digitalWrite(m2b, LOW);
}
else if(val == 'S')
{
digitalWrite(m1a, LOW);
digitalWrite(m1b, LOW);
digitalWrite(m2a, LOW);
digitalWrite(m2b, LOW);
delay(1000);
digitalWrite(m2a, HIGH);
}
}
// End of program
没有错误的按摩请帮助。 我在手机上使用this app,最后11行代码是(val =='S'),用于表示应用程序中的停止按钮。
我只需要在按下按钮时移动它,而在没有按下任何按钮时停止它。不需要停止按钮。
答案 0 :(得分:1)
if( val == '1') // Forward
{
digitalWrite(m1a, HIGH);
digitalWrite(m1b, LOW);
digitalWrite(m2a, HIGH);
digitalWrite(m2b, LOW);
delay(1);
digitalWrite(m1a, LOW);
digitalWrite(m2a, LOW);
}
收件人
if( val == '1') // Forward
{
digitalWrite(m1a, HIGH);
digitalWrite(m1b, LOW);
digitalWrite(m2a, HIGH);
digitalWrite(m2b, LOW);
delay(1);
digitalWrite(m1a, LOW);
digitalWrite(m2a, LOW);
val = ' ';
}