换句话说,可以实现的继承深度是有限的。
目前,我的深度为2,祖父母->父母->孩子,我遇到了一个问题,杰克逊可以反序列化给父母,然后抛出UnrecognizedPropertyException
。但这是正确的,但是子类确实拥有该属性,我相信我已经为Jackson添加了正确的Type信息,以反序列化该孩子。
此测试显示了问题:
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonSubTypes;
import com.fasterxml.jackson.annotation.JsonTypeInfo;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.annotation.JsonDeserialize;
import com.fasterxml.jackson.databind.annotation.JsonPOJOBuilder;
import lombok.EqualsAndHashCode;
import lombok.Getter;
import lombok.Value;
import lombok.experimental.SuperBuilder;
import org.junit.Assert;
import org.junit.Test;
import java.io.IOException;
import java.util.List;
public class JacksonInheritanceTest {
@Test
public void deserializeChildrenAsGrandParentList() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String grandparentsJson = "{" +
"\"list\":[{" +
"\"type\": \"parent\"," +
"\"value\": \"child\"," +
"\"someProperty\": \"foobar\"" +
"}]" +
"}";
GrandParentList grandparents = mapper.readValue(grandparentsJson, GrandParentList.class);
Assert.assertNotNull(grandparents);
}
@Test
public void deserializeParentAsGrandParent() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String parentJson = "{" +
"\"type\": \"parent\"," +
"\"value\": \"child\"" +
"}";
GrandParent grandparent = mapper.readValue(parentJson, GrandParent.class);
Assert.assertNotNull(grandparent);
}
@Test
public void deserializeChildAsGrandParent() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String grandparentJson = "{" +
"\"type\": \"parent\"," +
"\"value\": \"child\"," +
"\"someProperty\": \"foobar\"" +
"}";
GrandParent grandparent = mapper.readValue(grandparentJson, GrandParent.class);
Assert.assertNotNull(grandparent);
}
@Test
public void deserializeChildAsParent() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String childJson = "{" +
"\"type\": \"parent\"," +
"\"value\": \"child\"," +
"\"someProperty\": \"foobar\"" +
"}";
Parent parent = mapper.readValue(childJson, Parent.class);
Assert.assertNotNull(parent);
}
@Test
public void deserializeAsChild() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String child1 = "{" +
"\"type\": \"parent\"," +
"\"value\": \"child\"," +
"\"someProperty\": \"foobar\"" +
"}";
Child child = mapper.readValue(child1, Child.class);
Assert.assertNotNull(child);
}
}
class GrandParentList {
@JsonProperty
List<GrandParent> list;
}
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, property = "type", visible = true)
@JsonSubTypes({
@JsonSubTypes.Type(value = Parent.class,
name = "parent")
})
@Getter
@SuperBuilder
@JsonDeserialize(builder = GrandParent.GrandParentBuilderImpl.class)
class GrandParent {
@JsonProperty("type")
private String type;
@JsonPOJOBuilder(withPrefix = "")
static final class GrandParentBuilderImpl extends GrandParentBuilder<GrandParent, GrandParent.GrandParentBuilderImpl> {
}
}
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, property = "value", visible = true)
@JsonSubTypes({
@JsonSubTypes.Type(value = Child.class, name = "child")
})
@Getter
@SuperBuilder
@JsonDeserialize(builder = Parent.ParentBuilderImpl.class)
class Parent extends GrandParent {
@JsonProperty
private String value;
@JsonPOJOBuilder(withPrefix = "")
static final class ParentBuilderImpl extends ParentBuilder<Parent, ParentBuilderImpl> {
}
}
@EqualsAndHashCode(callSuper = true)
@Value
@SuperBuilder
@JsonDeserialize(builder = Child.ChildBuilderImpl.class)
class Child extends Parent {
@JsonProperty
private String someProperty;
@JsonPOJOBuilder(withPrefix = "")
static final class ChildBuilderImpl extends ChildBuilder<Child, ChildBuilderImpl> {
}
}
答案 0 :(得分:0)
在ObjectMapper对象上设置配置:
mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES,false);
答案 1 :(得分:0)
以下是如何定义具有多个级别的继承:
您要反序列化最终类型为“子级”的GrandParent列表
{
"list":[{
"type": "child",
"someProperty": "foobar"
}]
}
并且继承树是:
GrandParent
Parent
Child(someProperty:String)
您必须在顶级@JsonTypeInfo(...)定义“类型”属性。 您可以在子级别上重复此操作,但如果仅序列化/反序列化祖父母,则不需要这样做。 然后在每个父级别(Parent和GrandParent类)上,定义子类型,就像使用@JsonSubTypes一样。
代码
public class JacksonInheritanceTest2 {
@Test
public void deserializeChildrenAsGrandParentList() throws IOException {
ObjectMapper mapper = new ObjectMapper();
String grandparentsJson = "{" +
"\"list\":[{" +
"\"type\": \"child\"," +
"\"someProperty\": \"foobar\"" +
"}]" +
"}";
GrandParentList grandparents = mapper.readValue(grandparentsJson, GrandParentList.class);
Assertions.assertNotNull(grandparents);
}
}
class GrandParentList {
@JsonProperty
List<GrandParent> list;
}
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, property = "type", visible = true)
@JsonSubTypes({
@JsonSubTypes.Type(value = Parent.class,name = "parent"),
//@JsonSubTypes.Type(value = Child.class, name = "child")
})
class GrandParent {
@JsonProperty("type")
private String type;
}
//@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, property = "type", visible = true)
@JsonSubTypes({
@JsonSubTypes.Type(value = Child.class, name = "child")
})
class Parent extends GrandParent {
@JsonProperty
private String value;
}
@JsonSubTypes({
@JsonSubTypes.Type(value = Child.class, name = "child")
})
class Child extends Parent {
@JsonProperty
private String someProperty;
public String getSomeProperty() {
return someProperty;
}
public void setSomeProperty(String someProperty) {
this.someProperty = someProperty;
}
}
您所做的错误:
侧节点:Assertions
来自junit5,它与junit4中的Assert
相同