我已经写下了strptime用来将我的字符串解析为datetime的格式,但是在没有明确原因的情况下它一直失败。
我有一个要解析的日期/时间字符串:'2019-06-17T05:35:30' 我给它提供了以下格式:'%y-%m-%dT%H:%M:%S' 显然不匹配。
我尝试使用replace方法将'T'替换为空格,并相应地更改了格式,无济于事。
tmpTime = eval(data.columns[2])['sleep'][0]['startTime'][:19] #Excluded
#milliseconds by trimming whatever is after the '.', including the '.' itself.
dt = datetime.strptime(tmpTime, '%y-%m-%dT%H:%M:%S')
ValueError Traceback (most recent call last)
<ipython-input-13-a379ef67d5ba> in <module>
20 tmpTime = eval(data.columns[2])['sleep'][0]['startTime'][:19]
21 #tmpTime = tmpTime.replace("T"," ")
---> 22 dt = datetime.strptime(tmpTime, '%y-%m-%dT%H:%M:%S')
~\AppData\Local\Programs\Python\Python37\lib\_strptime.py in _strptime_datetime(cls, data_string, format)
575 """Return a class cls instance based on the input string and the
576 format string."""
--> 577 tt, fraction, gmtoff_fraction = _strptime(data_string, format)
578 tzname, gmtoff = tt[-2:]
579 args = tt[:6] + (fraction,)
~\AppData\Local\Programs\Python\Python37\lib\_strptime.py in _strptime(data_string, format)
357 if not found:
358 raise ValueError("time data %r does not match format %r" %
--> 359 (data_string, format))
360 if len(data_string) != found.end():
361 raise ValueError("unconverted data remains: %s" %
ValueError: time data '2019-06-17T05:35:30' does not match format '%y-%m-%dT%H:%M:%S'
Supposed to parse correctly into a datetime object, fails.
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
<ipython-input-13-a379ef67d5ba> in <module>
20 tmpTime = eval(data.columns[2])['sleep'][0]['startTime'][:19]
21 #tmpTime = tmpTime.replace("T"," ")
---> 22 dt = datetime.strptime(tmpTime, '%y-%m-%dT%H:%M:%S')
~\AppData\Local\Programs\Python\Python37\lib\_strptime.py in _strptime_datetime(cls, data_string, format)
575 """Return a class cls instance based on the input string and the
576 format string."""
--> 577 tt, fraction, gmtoff_fraction = _strptime(data_string, format)
578 tzname, gmtoff = tt[-2:]
579 args = tt[:6] + (fraction,)
~\AppData\Local\Programs\Python\Python37\lib\_strptime.py in _strptime(data_string, format)
357 if not found:
358 raise ValueError("time data %r does not match format %r" %
--> 359 (data_string, format))
360 if len(data_string) != found.end():
361 raise ValueError("unconverted data remains: %s" %
ValueError: time data '2019-06-17T05:35:30' does not match format '%y-%m-%dT%H:%M:%S'
答案 0 :(得分:1)
年份的字符串格式错误,应将其表示为'%Y'。例如:
tmpTime = '2019-06-17T05:35:30'
dt = datetime.strptime(tmpTime, '%Y-%m-%dT%H:%M:%S')
>>>dt
datetime.datetime(2019, 6, 17, 5, 35, 30)
您可以找到正确的日期时间解析格式here