Question

如何在字符串的特定长度中计算特定单词。让我们考虑一下一个字符串-“足球是一款很棒的游戏，它是全世界最受欢迎的游戏，这不仅是一场比赛，而且还是各国共同欢聚的节日，也是最令人兴奋的时刻”。字符串的总长度为145。我想计算一下字符串的每100个字符中有多少个“是”。

让我们考虑长度为100的字符串的第一部分，即-“足球是一款很棒的游戏，它是全世界最受欢迎的游戏，它不仅是一款游戏，而且还是一款”。在这里，我们发现100个字符中有3个“是”。琴弦的其余部分是“为各国欢聚的节日，这也是最令人兴奋的”，它的长度为69，长度为1。

我可以从一个字符串中找到给定单词的数目，但不能从特定的字符串长度中找到。这是我的下面的代码-

string word = "is";
string sentence = "Football is a great game It is most popular game all over the world It is not only a game but also a festival of get together for the nations which is most exciting too";
int count = 0;
foreach (Match match in Regex.Matches(sentence, word, RegexOptions.IgnoreCase))
{
    count++;
}
Console.WriteLine("{0}" + " Found " + "{1}" + " Times", word, count);`

输入：

string-“足球是一款很棒的游戏，它是全世界最受欢迎的游戏，这不仅是一场比赛，而且还是各国共同欢聚的节日，也是最令人兴奋的一次”

单词-'是'

长度-100

输出：

在第一部分：给定单词数= 3

第二部分：给定单词数= 1

Answer 1

创建具有所需长度的子字符串，然后使用linq进行计数。

int length = 100;
string word = "is";
string sentence = "Football is a great game It is most popular game all over the world It is not only a game but also a festival of get together for the nations which is most exciting too";
//Substring with desired length
sentence = sentence.Substring(0, length);
int count = 0;
//creating an array of words
string[] words = sentence.Split(Convert.ToChar(" "));
//linq query
count = words.Where(x => x == word).Count();
Debug.WriteLine(count);

对于第二部分，请创建一个从100开始到字符串末尾的子字符串。

Answer 2

尝试以下代码：

public class JavaApplication22 {

    public static void main(String[] args) {
        String str = "Football is a great game It is most popular game all over the world It is not only a game but also a festival of get together for the nations which is most exciting too";
        String pattern = "is";
        int count = 0;
        int a = 0;

        while((a = str.indexOf(pattern, a)) != -1){
            a += pattern.length();
            count++;
        }
        System.out.println("Count is : " + count);
    }
}

如何计算特定长度的字符串中的特定单词数

2 个答案: