我有一个需要排序的课程。使用此类的向量,排序时会出现错误“无效比较器”。
我在课堂上超载了“ <”运算符,并且遵循了严格的弱排序。
如本post中所述。
sort
需要严格的弱排序。您的comparator
不是一个。除其他外,对于严格的弱排序,comp(x, x)
必须为 false 。
bool outlierScore::operator<(const outlierScore& other) {
if (score < other.score)
return score < other.score;
else if (coreDistance < other.coreDistance)
return coreDistance < other.coreDistance;
else if (id < other.id)
return id < other.id;
else
return false;
}
这是重载的运算符函数,它的作用实际上是尝试按离群分数按升序排序,其中核心距离用于中断 离群值得分关系和用于打破核心距离关系的ID。
堆栈跟踪显示了此阶段出现的错误。
template <class _Pr, class _Ty1, class _Ty2>
constexpr bool _Debug_lt_pred(_Pr&& _Pred, _Ty1&& _Left, _Ty2&& _Right) _NOEXCEPT_COND(
noexcept(_Pred(_Left, _Right))
&& noexcept(_Pred(_Right, _Left))) { // test if _Pred(_Left, _Right) and _Pred is strict weak ordering
const auto _Result = static_cast<bool>(_Pred(_Left, _Right));
if (_Result) {
_STL_VERIFY(!_Pred(_Right, _Left), "invalid comparator");
}
return _Result;
}
我找不到问题。任何帮助都会很棒。
最小可复制示例:
class outlierScore
{
private:
double coreDistance;
public:
double score;
int id;
}
vector <vector<double>> x = {
{0,0.889528896739179,0.536626916823739},
{1,1.30766765703343,0.684794721931497},
{2,0.936505261432846,0.559870334496815}
};
vector<outlierScore> test;
test.push_back(outlierScore(x[0][2], x[0][1], x[0][0]));
test.push_back(outlierScore(x[1][2], x[1][1], x[1][0]));
test.push_back(outlierScore(x[2][2], x[2][1], x[2][0]));
包含看起来像如下的outlierScore对象
{id, coreDistance, score}
出现错误的地方:
sort(test.begin(), test.end());
答案 0 :(得分:10)
您的实现不正确。
android {
...
...
dexOptions {
incremental true
javaMaxHeapSize "4G"
}
...
...
}
或
bool outlierScore::operator<(const outlierScore& other) const {
return (score < other.score) ||
(score == other.score && coreDistance < other.coreDistance) ||
(score == other.score && coreDistance == other.coreDistance && id < other.id);
}
答案 1 :(得分:10)
除了方法不是const
之外,此运算符不满足严格的弱排序。
bool outlierScore::operator<(const outlierScore& other) {
if (score < other.score)
return score < other.score;
else if (coreDistance < other.coreDistance)
return coreDistance < other.coreDistance;
else if (id < other.id)
return id < other.id;
else
return false;
}
例如,如果所有字段都是整数。
a.score = 0 ; a.coreDistance = 1
b.score = 1 ; b.coreDistance = 0
对于这些值,以下应该为false,但返回true:
a < b && b < a
您还应该检查是否相等:
bool outlierScore::operator<(const outlierScore& other) {
if (score != other.score)
return score < other.score;
else if (coreDistance != other.coreDistance)
return coreDistance < other.coreDistance;
else
return id < other.id;
}