Question

句子类

class sentence
{   
    public:
        sentence(); 
        ~sentence();
        void testing(sentence *& s);
        sentence operator+=(char * sentence_to_add);
    protected:
        node * head;
};

实施（不正确，只测试是否有效）

sentence sentence::operator+=(char * sentence_to_add) 
{
    cout << "testing" << endl;
    return *this;
}

测试所述运营商

void sentence::testing(sentence *& s)
{
    char * test_string = new char[5000];
    cout << "please enter a string: " << endl;
    cin.getline(test_string, 5000, '\n');
    s += test_string;
}

G ++编译器错误

sentence.cpp: In member function âvoid sentence::testing(sentence*&)â:
sentence.cpp:124:7: error: invalid operands of types âsentence*â and âchar*â to binary âoperator+â
sentence.cpp:124:7: error:   in evaluation of âoperator+=(class sentence*, char*)â

我做错了什么？因为从技术上讲这应该有效。由于左值是指向类对象的指针，因此右值是char数组。所以我很确定操作数不是无效的......

编辑/更新：原型

sentence & operator+=(const char * sentence_to_add);

实施

sentence & sentence::operator+=(const char * sentence_to_add) 
{
    cout << "testing" << endl;
    return *this;
}

Answer 1

你的函数需要一个指针，而不是一个对象。只需参考（sentence&。）

另外，您的运营商应该返回参考，而不是副本。

重载+ =运算符时无效的操作数错误

1 个答案: