Question

这里有两个对象，如果在object2中找到，我需要比较它们并从object1返回特定值。

object1 = {
  "body": {
    "items": [
      {
        "data": {
          "name": "Smith",
          "status": "Ready",
          "userinfo": [
            {
              "dob": "01/01/2000",
              "nickname": "Joe"
            }
          ]
        },
        "workinfo": {
          "company": "mycompany",
          "address": "101 Main str."
        }
      },
      {
        "data": {
          "name": "Luke",
          "status": "Ready",
          "userinfo": [
            {
              "dob": "01/01/2001",
              "nickname": "LL"
            }
          ]
        },
        "workinfo": {
          "company": "mycompany",
          "address": "101 Main str."
        }
      }
    ]
  }
}

Object2甚至很简单：

object2 = {
  "items": [
    {
      "name": "Smith",
      "status": "Ready"
    },
    {
      "name": "Luke",
      "status": "Ready"
    }
  ]
}

因此，如果在Object2 items.name中找到了Object1 body.items [x] .data.name，那么最后我需要获得这样的新对象：

object3 = {{name: "Smith", status: "Ready"}, {name: "Luke", status: "Ready"}}

Answer 1

您可以使用过滤器查找：

var obj1 = {
  "body": {
    "items": [{
        "data": {
          "name": "Smith",
          "status": "Ready",
          "userinfo": [{
            "dob": "01/01/2000",
            "nickname": "Joe"
          }]
        },
        "workinfo": {
          "company": "mycompany",
          "address": "101 Main str."
        }
      },
      {
        "data": {
          "name": "Luke",
          "status": "Ready",
          "userinfo": [{
            "dob": "01/01/2001",
            "nickname": "LL"
          }]
        },
        "workinfo": {
          "company": "mycompany",
          "address": "101 Main str."
        }
      }
    ]
  }
}

var obj2 = {
  "items": [{
      "name": "Smith",
      "status": "Ready"
    },
    {
      "name": "Luke",
      "status": "Ready"
    }
  ]
}

var output = obj2.items.filter(({name}) => obj1.body.items.find(({data}) => name === data.name))

console.log(output)

过滤器将返回所有通过查找条件的对象，也就是说，如果名称在obj1中找到

Answer 2

您可以使用_.intersectionWith()从obj2返回项目，它们的name等于data.name项目中的obj2：

const obj1 = {"body":{"items":[{"data":{"name":"Smith","status":"Ready","userinfo":[{"dob":"01/01/2000","nickname":"Joe"}]},"workinfo":{"company":"mycompany","address":"101 Main str."}},{"data":{"name":"Luke","status":"Ready","userinfo":[{"dob":"01/01/2001","nickname":"LL"}]},"workinfo":{"company":"mycompany","address":"101 Main str."}}]}}
const obj2 = {"items":[{"name":"Smith","status":"Ready"},{"name":"Luke","status":"Ready"}]}

const result = _.intersectionWith(obj2.items, obj1.body.items, 
  (a, b) => _.get(a, 'name') === _.get(b, 'data.name')
)

console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.js"></script>

Answer 3

使用ES6，使用Array.filter和Array.some可以轻松完成任务：

const obj1 = {"body":{"items":[{"data":{"name":"Smith","status":"Ready","userinfo":[{"dob":"01/01/2000","nickname":"Joe"}]},"workinfo":{"company":"mycompany","address":"101 Main str."}},{"data":{"name":"Luke","status":"Ready","userinfo":[{"dob":"01/01/2001","nickname":"LL"}]},"workinfo":{"company":"mycompany","address":"101 Main str."}}]}}
const obj2 = {"items":[{"name":"Smith","status":"Ready"},{"name":"Luke","status":"Ready"}]}

const r = obj2.items.filter(x => obj1.body.items.some(y => y.data.name == x.name))

console.log(r)

由于对象在obj2中具有正确的布局，因此可以从此处开始并针对obj1进行过滤。

如何用lodash比较两个对象并返回新对象？

3 个答案: