Question

我有两个对象。如果两个对象中均出现键，则我希望第一个对象的值作为键，第二个对象的值作为值。

var obj1 = {a:"value1",b:"value2",c:"value3"}
var obj2 = {a:"index1",b:"index2",c:"index3",d:"index4"};

输出应如下所示：

{"value1":"index1","value2":"index2","value3":"index3"}

我该怎么做？

Answer 1

从第一个对象获取条目（[键，值]），如果键obj2中也存在键，则使用reduce将第二个对象的值组合起来：

const obj1 = {a:"value1",b:"value2",c:"value3"};
const obj2 = {a:"index1",b:"index2",c:"index3",d:"index4"};

const result = Object.entries(obj1) // get the entries
  .reduce((r, [k, v]) => {
    if(k in obj2) { // if the key exists in obj2
      r[v] = obj2[k]; // use the value from obj1 as the key, with the value from obj2
    }
  
    return r
  }, {});
  
console.log(result);

使用lodash，可以从两个对象中获取密钥，并使用_.intersection()查找公用密钥。然后，您可以使用_.at()从每个对象获取值，并使用_.zipObject()将两个值的数组组合到一个对象中：

const obj1 = {a:"value1",b:"value2",c:"value3"};
const obj2 = {a:"index1",b:"index2",c:"index3",d:"index4"};

// get the keys that exists in both objects
const keys = _.intersection(_.keys(obj1), _.keys(obj2));
const result = _.zipObject( // combine arrays of values to an object
  _.at(obj1, keys), // get the values from obj1
  _.at(obj2, keys), // get the values from obj2
)

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.15/lodash.js"></script>

Answer 2

迭代 obj1 的键，并使用 obj1 的值作为键，并使用 obj2 的值作为值。

const obj1 = {a:"value1",b:"value2",c:"value3"}
const obj2 = {a:"index1",b:"index2",c:"index3",d:"index4"};

const newObj = {};

for (let key in obj1)
    if (obj2[key])
    	newObj[obj1[key]] = obj2[key];

console.log(newObj);

Answer 3

var obj1 = {a:"value1",b:"value2",c:"value3"}
var obj2 = {a:"index1",b:"index2",c:"index3",d:"index4"};

var obj = {};

for( let i in obj1) {
  if(obj2.hasOwnProperty(i))
    obj[ obj1[i] ] = obj2[i];
}

console.log(obj)

Answer 4

var obj1 = {a:"value1",b:"value2",c:"value3"}
var obj2 = {a:"index1",b:"index2",c:"index3",d:"index4"};

/* iterate on all the props of obj1*/
const result=Object.keys(obj1).reduce((acc,obj1Prop)=>{
/*if obj2[value of propObj1] is not undefined */
if(typeof obj2[obj1Prop] !== "undefined"){
// assign the value of obj2[value of propObj1] to accumulator
	acc[obj1[obj1Prop]]=obj2[obj1Prop];
  }
  return acc;

},{})
//result contains the result
console.log(result)

Javascript比较制作新对象的两个对象键

4 个答案: