Question

我有一个python列表（如下所示），其中包含两种类型的字符串：一种类似于'1556294808 2019-04-26 21:36:48 +0530'，另一种类似于'3个文件已更改，126插入（+），18个删除（-）'，但这些位置并非严格位于备用位置。

我想通过在类型为1的两个字符串之间插入'0个文件已更改，0个插入（+），0个删除（-）'来在交替位置使用这两种类型的字符串，以防它们位于连续的位置。元素的顺序不得更改。

['1556294808 2019-04-26 21:36:48 +0530', ' 1 file changed, 1 deletion(-)', '1545318890 2018-12-20 20:44:50 +0530', '1545318858 2018-12-20 20:44:18 +0530', ' 3 files changed, 126 insertions(+), 18 deletions(-)', '1545208408 2018-12-19 14:03:28 +0530', '1545208369 2018-12-19 14:02:49 +0530', ' 2 files changed, 352 insertions(+), 12 deletions(-)', '1545134701 2018-12-18 17:35:01 +0530', ' 3 files changed, 134 insertions(+), 1 deletion(-)', '1545116120 2018-12-18 12:25:20 +0530', '1545115969 2018-12-18 12:22:49 +0530', ' 2 files changed, 25 insertions(+), 17 deletions(-)', '1545114797 2018-12-18 12:03:17 +0530', '1545114768 2018-12-18 12:02:48 +0530', ' 2 files changed, 107 insertions(+), 17 deletions(-)', '1545107389 2018-12-18 09:59:49 +0530', ' 3 files changed, 55 insertions(+), 16 deletions(-)', '1545051306 2018-12-17 18:25:06 +0530', '1545051282 2018-12-17 18:24:42 +0530', ' 3 files changed, 121 insertions(+), 1 deletion(-)', '1545031219 2018-12-17 12:50:19 +0530', '1545031091 2018-12-17 12:48:11 +0530', ' 3 files changed, 327 insertions(+), 6 deletions(-)', '1545027187 2018-12-17 11:43:07 +0530', '1545027168 2018-12-17 11:42:48 +0530', ' 2 files changed, 79 insertions(+), 11 deletions(-)', '1545022804 2018-12-17 10:30:04 +0530', ' 3 files changed, 47 insertions(+), 8 deletions(-)']

Answer 1

这应该为您解决工作。下面，我遍历整个列表以检查+0530是否为data = [] for i in range(len(y)): if "+0530" in y[i]: data.append(y[i]) if "+0530" in y[i+1]: data.append("0 files changed, 0 insertions(+)") else: data.append(y[i])，因为它看起来像每个时间戳一样。如果需要，可以编写函数来检查其时间戳，这将更加有效。

data

1556294808 2019-04-26 21:36:48 +0530 1 file changed, 1 deletion(-) 1545318890 2018-12-20 20:44:50 +0530 0 files changed, 0 insertions(+) 1545318858 2018-12-20 20:44:18 +0530 3 files changed, 126 insertions(+), 18 deletions(-)的输出：

myList = [Qt.Key_A,Qt.Key_B,Qt.Key_C,... Qt.Key_Z]

if event.text() in myList:
   print("In My List")

Answer 2

如果我正确理解了这个问题，则下面的代码应该可以工作，它基本上是遍历列表，并且如果找到两个连续的“ date”字符串，则在两者之间插入一个字符串。该循环向后进行，以避免出现插入新元素的引用问题。

import datetime as dt

items = ['1556294808 2019-04-26 21:36:48 +0530', ' 1 file changed, 1 deletion(-)', '1545318890 2018-12-20 20:44:50 +0530', '1545318858 2018-12-20 20:44:18 +0530', ' 3 files changed, 126 insertions(+), 18 deletions(-)', '1545208408 2018-12-19 14:03:28 +0530', '1545208369 2018-12-19 14:02:49 +0530', ' 2 files changed, 352 insertions(+), 12 deletions(-)', '1545134701 2018-12-18 17:35:01 +0530', ' 3 files changed, 134 insertions(+), 1 deletion(-)', '1545116120 2018-12-18 12:25:20 +0530', '1545115969 2018-12-18 12:22:49 +0530', ' 2 files changed, 25 insertions(+), 17 deletions(-)', '1545114797 2018-12-18 12:03:17 +0530', '1545114768 2018-12-18 12:02:48 +0530', ' 2 files changed, 107 insertions(+), 17 deletions(-)', '1545107389 2018-12-18 09:59:49 +0530', ' 3 files changed, 55 insertions(+), 16 deletions(-)', '1545051306 2018-12-17 18:25:06 +0530', '1545051282 2018-12-17 18:24:42 +0530', ' 3 files changed, 121 insertions(+), 1 deletion(-)', '1545031219 2018-12-17 12:50:19 +0530', '1545031091 2018-12-17 12:48:11 +0530', ' 3 files changed, 327 insertions(+), 6 deletions(-)', '1545027187 2018-12-17 11:43:07 +0530', '1545027168 2018-12-17 11:42:48 +0530', ' 2 files changed, 79 insertions(+), 11 deletions(-)', '1545022804 2018-12-17 10:30:04 +0530', ' 3 files changed, 47 insertions(+), 8 deletions(-)']
new_item = ' 0 files changed, 0 insertions(+), 0 deletions(-)'

fmt = ['%Y %m %d','%H %M %S','%z']
def check_for_date(item, fmt):
    try:
        date = item.split()
        for i in range(3):
            dt.datetime.strptime(date[i+1].replace('-',' ').replace(':',' '), fmt[i])
        return True
    except ValueError as err:
        return False

for ii in range(len(items)-1,0,-1):
    if (check_for_date(items[ii], fmt)) and (check_for_date(items[ii-1], fmt)):
        items.insert(ii, new_item)

如何针对特定问题在python列表中的某些位置插入数据？

2 个答案: