Question

我有这样的CSV文件：

Year,Make,Model,Description,Price
1997,Ford,E350,"ac, abs, moon",3000.00
1999,Chevy,"Venture ""Extended Edition""","",4900.00
1999,Chevy,"Venture ""Extended Edition, Very Large""","",5000.00
1996,Jeep,Grand Cherokee,"MUST SELL! ""TODAY""
air, moon roof, loaded",4799.00

如何将其转换为二维数组而不会将最后一行放到自己的数组中？

以下是问题的说明（也在此https://3v4l.org/HAJh1上托管）：

$s2=<<<EOD
Year,Make,Model,Description,Price
1997,Ford,E350,"ac, abs, moon",3000.00
1999,Chevy,"Venture ""Extended Edition""","",4900.00
1999,Chevy,"Venture ""Extended Edition, Very Large""","",5000.00
1996,Jeep,Grand Cherokee,"MUST SELL! ""TODAY""
air, moon roof, loaded",4799.00
EOD;

$lines=str_getcsv($s2,"\n");
print_r($lines);

还有所讨论的错误（尽管在撰写本文时，PHP开发人员尚未将其识别为错误）：https://bugs.php.net/bug.php?id=55763

有"solutions" out there，但似乎没有一个能解决这个例子。

Answer 1

str_getcsv()期望该字符串是一个CSV记录，而不是整个CSV文件。

如果内存中有CSV文件，则可以使用php://memory将其转换为可以用fgetcsv()读取的流。这样可以正确解析记录。

<?php
$s2=<<<EOD
Year,Make,Model,Description,Price
1997,Ford,E350,"ac, abs, moon",3000.00
1999,Chevy,"Venture ""Extended Edition""","",4900.00
1999,Chevy,"Venture ""Extended Edition, Very Large""","",5000.00
1996,Jeep,Grand Cherokee,"MUST SELL! ""TODAY""
air, moon roof, loaded",4799.00
EOD;
$stream = fopen("php://memory", "r+");
fwrite($stream, $s2);
rewind($stream);
while ($row = fgetcsv($stream)) {
  print_r($row);
}

如果CSV实际上在文件中，则只需打开文件并使用fgetcsv()来读取文件即可。

PHP：在引号内寻找str_getcsv换行错误的解决方法

1 个答案: