Question

我正在将Eclipse for Java与AWS Toolkit结合使用。我运行这段代码：

public class Main {

    public static void main(String[] args) {

        AmazonCognitoIdentityClient client = new AmazonCognitoIdentityClient();

        client.trial();

        UserType userType = client.signUp();

    }

}

public class AmazonCognitoIdentityClient {

    public void trial() {

        AWSCognitoIdentityProvider cognitoClient = getAmazonCognitoIdentityClient();
        System.out.println(userPoolType.getSchemaAttributes());

    }

    public AWSCognitoIdentityProvider getAmazonCognitoIdentityClient() {
        ClasspathPropertiesFileCredentialsProvider propertiesFileCredentialsProvider = 
                new ClasspathPropertiesFileCredentialsProvider();

        return AWSCognitoIdentityProviderClientBuilder.standard()
                .withCredentials(propertiesFileCredentialsProvider)
                .withRegion("us-east-1")
                .build();

    }

    public UserType signUp() {

        AWSCognitoIdentityProvider cognitoClient = getAmazonCognitoIdentityClient();
        AdminCreateUserRequest cognitoRequest = new AdminCreateUserRequest()
                .withUserPoolId("us-east-1_PJa8U1lw3")
                .withUsername("yahoo")
                .withUserAttributes(
                        new AttributeType()
                        .withValue("dbrower256@yahoo.com"),
                        new AttributeType()
                        .withName("sub")
                        .withValue("sub"),
                        new AttributeType()
                        .withName("name")
                        .withValue("Daniel"),
                        new AttributeType()
                        .withName("given_name")
                        .withValue("Daniel"),
                        new AttributeType()
                        .withName("family_name")
                        .withValue("Brower"),
                        new AttributeType()
                        .withName("phone_number")
                        .withValue("9032761046"),
                        new AttributeType()
                        .withName("email_verified")
                        .withValue("true"))
                .withTemporaryPassword("TEMPORARY_PASSWORD")
                .withMessageAction("SUPPRESS")
                .withDesiredDeliveryMediums(DeliveryMediumType.EMAIL)
                .withForceAliasCreation(Boolean.FALSE);

        AdminCreateUserResult createUserResult = cognitoClient.adminCreateUser(cognitoRequest);
        UserType cognitoUser = createUserResult.getUser();

        return cognitoUser;

    }

}

我在控制台视图中得到了这个

[... {名称：名称，AttributeDataType：字符串，DeveloperOnlyAttribute：false，可变：true，必填：false，StringAttributeConstraints：{MinLength：0，MaxLength：2048}} ...]

线程“ main”中的异常com.amazonaws.services.cognitoidp.model.InvalidParameterException：检测到1个验证错误：“ userAttributes.1.member.name”处的值为null未能满足约束条件：Member不能为null ..

从getSchemaAttributes（）的打印中可以看到，“ name”不是必需的。为什么我会收到错误消息，说它不能为空？

Answer 1

您尝试更改此代码：

                .withUserAttributes(
                        new AttributeType()
                        .withValue("dbrower256@yahoo.com"),

类似：

                .withUserAttributes(
                        new AttributeType()
                        .withName(...)
                        .withValue("dbrower256@yahoo.com"),

AWSCognitoIdentityProvider.adminCreateUser（...）无法满足约束：成员不能为空

1 个答案: