Question

nc.variables[i].units显示错误attribute not found。我试图从netcdf文件中提取数据。如何提取特定经度或纬度的数据？

from netCDF4 import Dataset

nc=Dataset("test.nc",'r')

for i in nc.variables:

    print(i,nc.variables[i].units,nc.variables[i].shape) 

lat=nc.variables['lat'][:]
print(lat)

输出如下：

area meter2 (128, 256)
lat degrees_north (128,)
Traceback (most recent call last):
File "C:\Users\harsh\Desktop\cv\test_netcdf.py", line 7, in <module>
print(i,nc.variables[i].units,nc.variables[i].shape) #nc.variable[i].units
File "netCDF4\_netCDF4.pyx", line 4303, in 
netCDF4._netCDF4.Variable.__getattr__
File "netCDF4\_netCDF4.pyx", line 4114, in 
netCDF4._netCDF4.Variable.getncattr
File "netCDF4\_netCDF4.pyx", line 1392, in netCDF4._netCDF4._get_att
File "netCDF4\_netCDF4.pyx", line 1857, in 
netCDF4._netCDF4._ensure_nc_success
AttributeError: NetCDF: Attribute not found

Answer 1

仔细阅读本节

for i in nc.variables:

    print(i,nc.variables[i].units,nc.variables[i].shape)

在此for循环中，我不是整数。由于对每个循环将其评估为a，因此它代表当前变量，而不是该变量所在的索引。您在这里有几个选择

选择一：改为使用范围

for i in range(len(nc.variables)):

    print(i,nc.variables[i].units,nc.variables[i].shape)

选项二：使用zip引用变量和整数
正如Bart所指出的那样，枚举是一种更好的方法。看到他对此的评论

for i, variable in zip(range(len(nc.variables)), nc.variables):

    print(i, variable.units, variable.shape)

选择三：避免完全使用我

for variable in nc.variables:

    print(variable.units, variable.shape)

nc.variables [i] .units从netcdf文件提取数据时显示错误

1 个答案: