Question

如何显示数据字符的某些百分比。假设我需要显示名称中50％的字符，例如“讲师”。

考试中有人问我这个问题，我没有这样做。

create table employee(
e_id int(10) , 
empname char(10),
designation char(10),
salary int(10),
age int(10),
deptid int(10),
job varchar(30));

insert into employee values(101,'Hassan','TA',46000,20,10,"manager");
insert into employee values(102,'Tahir','Poem',43000,45,10,"manager");
insert into employee values(103,'Ahmed','Hand',36000,27,20,"Analyst");
insert into employee values(104,'Imran','lecturer',24000,27,30,"Manager");
insert into employee values(105,'Furqan','teacher',36000,22,30,"Salesman");

select empname 
from employee 
where length(empname/2);

在尝试时，我得到了雇员的全名，而不是其姓名的半角字符。

Answer 1

可以使用LEFT()和LENGTH()：

SELECT LEFT(empname, LENGTH(empname)/2)
FROM employee

Answer 2

希望获得帮助，

50是您的百分比。您可以根据需要更改百分比。

SELECT SUBSTRING(empname, 1, ROUND( (length(empname)/100) * 50 ) ) AS ExtractString from employee

显示字符百分比

2 个答案: