Question

如何删除，而不是使用Swift解码字符串中的百分比转义字符。例如：

"hello%20there" 应该成为 "hellothere"

编辑：

我想在字符串中替换多个转义百分比的字符。所以： "hello%20there%0Dperson" 应该成为 "hellothereperson"

Answer 1

class MessagesManager {
   constructor() {
      this.msgs = (localStorage.getItem("messages"))?JSON.parse(localStorage.getItem("messages")):[];
}

add(author, message) {
    var msg = new Message(author, message)
    this.msgs.push(msg);
}

save() {
    localStorage.setItem("messages", JSON.stringify(this.msgs));
}

delete() {
    this.msgs = [];
    localStorage.removeItem("messages");
}

Answer 2

您可以使用正则表达式匹配%后跟两个数字：%[0-9a-fA-F]{2}

let myString = "hello%20there%0D%24person"
let regex = try! NSRegularExpression(pattern: "%[0-9a-fA-F]{2}", options: [])
let range = NSMakeRange(0, myString.characters.count)
let modString = regex.stringByReplacingMatchesInString(myString,
                                                       options: [],
                                                       range: range,
                                                       withTemplate: "")
print(modString)

Answer 3

您可以使用“removingPercentEncoding”方法

let precentEncodedString = "hello%20there%0Dperson"
let decodedString = precentEncodedString.removingPercentEncoding ?? ""

Answer 4

let input:String = "hello%20there%0Dperson"

 guard let output = input.stringByRemovingPercentEncoding else{
      NSLog("failed to remove percent encoding")
      return
  }

 NSLog(output)

，结果是

hello there
person

然后你可以删除空格

或者您可以通过正则表达式将其删除

"%([0-9a-fA-F]{2})"

从字符串中删除转义百分比的字符

4 个答案: