Question

我的硬币编码游戏python代码中有这个问题，问题是当它询问“是头还是尾巴？”时我只是说1或Heads（与2和Tails相同）而没有引号和引号，它并不能为我提供所需的答案。

我尝试在答案中使用引号，但这似乎也不起作用。

import random

money = 100

#Write your game of chance functions here
def coin_flip(choice, bet):
   choice = input("Heads or Tails?")
   coinnum = random.randint(1, 2)
   if coinnum == 1:
      return 1
   elif coinnum == 2:
      return 2
   win = bet*2
   if choice == "Heads" or "1":
       return 1
   elif choice == "Tails" or "2":
      return 2
   if choice == coinnum:
      print("Well done! You have won " + str(win) + " Dollars!")
   elif choice != coinnum:
      print("Sorry, you lost " + str(bet) + " Dollars!")

coin_flip("Heads", 100)

预期输出是“做得好！您赢了200美元！”或“对不起，您损失了100美元！”

Answer 1

这里要注意的第一件事是您使用return似乎是错误的。请查阅有关如何编写函数以及如何使用return的教程。

我认为这就是您想要做的：

import random

money = 100

#Write your game of chance functions here
def coin_flip(choice, bet):
   choice = input("Heads or Tails? ")
   coinnum = random.randint(1, 2)
   win = bet*2

   if choice == "Heads" or choice == "1":
      choicenum = 1
   elif choice == "Tails" or choice == "2":
      choicenum = 2
   else:
      raise ValueError("Invalid choice: " + choice)

   if choicenum == coinnum:
      print("Well done! You have won " + str(win) + " Dollars!")
   else:
      print("Sorry, you lost " + str(bet) + " Dollars!")

coin_flip("Heads", 100)

现在，让我们来看看我在您的代码中发现的错误：

return完全不合适，我不确定您打算在这里做什么。
if choice == "Heads" or "1"无效，"1"始终取值为true。正确的是：if choice == "Heads" or choice == "1":
elif choice != coinnum:是不必要的，如果它没有遇到if choice == coinnum:，那么简单的else:就足够了。

Python 3.x中的机会游戏？

1 个答案: