Question

mysql需要从一个表中获取数据，其中id与另一表中的列值相同。但是必须从另一个表中仅获取列值，其ID与其他两个表中的列值相同（IN）。

表如下：

带有列的表名sales_invoices（在下面我没有显示所有列，有一些列是问题所必需的）。
IdInvoices | Date

带有列的表名purchase_invoices
IdInvoicesP | Date

带有列的表名items
IdI | IdGoodsServices | IdInvoices

带有列的表名goods_services
IdGs（唯一值）

这是表格之间的链接
IdGs = IdGoodsServices
IdInvoices（items）= IdInvoices（sales_invoices）= IdInvoicesP

尝试了多种代码变体。在所有情况下，都会出错。下面是最后使用的代码。

SELECT count(DISTINCT `IdGs`) FROM `goods_services` WHERE `IdGs` IN 

  ( SELECT `IdGoodsServices` FROM `items` WHERE `IdInvoices` IN 

    ( SELECT `IdInvoices`, `IdInvoicesP` FROM 
    `sales_invoices`, `purchase_invoices` WHERE `Date` <= ? ) 

  )

要计算在特定日期之前发出（书写）的销售和购买发票中包含的IdGs（产品或商品/服务代码）。

goods_services和sales_invoices / purchase_invoices之间没有直接链接。表items链接到goods_services和（sales_invoices / purchase_invoices）

上面的代码出现错误
SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'Date' in where clause is ambiguous

尝试过的子-子只能从一张表中选择，得到一些结果且没有错误。
这是查询

SELECT count(DISTINCT `IdGs`) FROM `goods_services` WHERE `IdGs` IN 

  ( SELECT `IdGoodsServices` FROM `30u2s5r_items` WHERE `IdInvoices` IN 

    ( SELECT `IdInvoicesP` FROM 
    `30u2s5r_purchase_invoices` WHERE `Date` <= ? ) 

  )

下面是工作代码（根据我到目前为止的测试）。

SELECT count(DISTINCT `IdGs`) FROM `goods_services` WHERE `IdGs` IN 

 (SELECT `IdGoodsServices` FROM `items` WHERE 

 `IdInvoices` IN 

  (SELECT DISTINCT `IdInvoices` FROM `sales_invoices` 
  WHERE `sales_invoices`.`Date` <= ? ) 

   OR 

  `IdInvoices` IN 
  ( SELECT DISTINCT `IdInvoicesP` FROM `purchase_invoices` 
  WHERE `purchase_invoices`.`Date` <= ? ) 

)

Answer 1

使用Purchase_invoices.Date或sales_invoices.Date

Mysql SELECT ... WHERE IN（从多个表中选择多个子项）

1 个答案: