Question

我试图基于数据库中的user_id显示一些数据，但是它一直在显示此ValueError。谁能帮助我找出我做错了什么？

这是我的views.py

from django.shortcuts import render, get_object_or_404
from .models import user

def index(request):
    return render(request, 'pages/index.html')

def user(request, user_id):
    profile = get_object_or_404(user, pk=user_id)
    context = {
        'profile' : profile
    }
    return render(request, 'user/user.html', context)

Answer 1

由于您定义了名为<?php $string = "https://bitebtc.com/api/v1/market"; $decoded = file_get_contents($string); $percent = $decoded->percent; echo $percent; As you can see in the link, the expected output would be something like 1.3 or at least a floating number between 0 and 10, but I got nothing, or a php notice: Trying to get property of non-object; since it is not an error I guess the problem doesn't come from the non-object property thing...的函数，因此此处覆盖了对user模型的引用。

您可以在导入中使用别名，例如：

user

话虽如此，根据PEP-8 style guidelines，类的名称应写在from django.shortcuts import render, get_object_or_404 from .models import user as UserModel def index(request): return render(request, 'pages/index.html') def user(request, user_id): profile = get_object_or_404(UserModel, pk=user_id) context = { 'profile' : profile } return render(request, 'user/user.html', context)中，函数的名称应写在CamelCase中。因此，如果符合这些准则，则应将lowercase_separated_by_underscores模型重命名为user。

由于Django已经有一个名为User [Django-doc]的模型（在User中），因此您可能想要重命名为django.contrib.auth。

get_object_or_404（）的第一个参数必须是Model，Manager或QuerySet，而不是“ function”

1 个答案: