Question

我正在尝试生成Python代码以获取遵循特定格式的文本文件中的输出。我想要的格式是：如果在随后的几行中，条目的顺序在某一点相同，则删除到该点的所有条目（保留最后一个）并生成最终的文本文件。在以下各节中，我将描述我要做什么和得到什么。 Data File Python Code

outputfile = open('webgrapviz.txt', 'w')
for data in all_data:
    line=""
    for k,item in enumerate(data):
        if len(item)==0: continue
        if len(line)==0:
              line=line+'"'+item+'"'
        else:
              line=line+"-> "+'"'+item+'"'

    line = line + "\n"
    outputfile.write(line)
outputfile.close()

我得到的输出是：

"Subsea Production"-> "Subsea Landing String Services"-> "SenTURIAN E&A Well Test Subsea Landing String Electrohydraulic Operating System"
"Subsea Production"-> "Subsea Landing String Services"-> "SenTURIAN Large-Bore Subsea Landing String Electrohydraulic Operating System"
"Subsea Production"-> "InterventionConstrained & Subsea Applications"-> "MaxFORTE High-Reliability ESP System"
"Subsea Production"-> "Intervention-Constrained & Subsea Applications"-> "ZEiTECS Shuttle Rigless ESPReplacement System"
"Subsea Production"-> "OneSubsea, a Schlumberger company"

我想要的输出是：

"Subsea Production"-> "Subsea Landing String Services"-> "SenTURIAN E&A Well Test Subsea Landing String Electrohydraulic Operating System"
"Subsea Landing String Services"-> "SenTURIAN Large-Bore Subsea Landing String Electrohydraulic Operating System"
"Subsea Production"-> "InterventionConstrained & Subsea Applications"-> "MaxFORTE High-Reliability ESP System"
"Intervention-Constrained & Subsea Applications"-> "ZEiTECS Shuttle Rigless ESPReplacement System"
"Subsea Production"-> "OneSubsea, a Schlumberger company"

Answer 1

首先想到的是，也许在性能方面有更好的方法。

outputfile = open('webgrapviz.txt', 'w')
prev_data = []
for data in all_data:
  data = [x for x in data if x] # Filter empty strings
  if not data:
    continue
  # Compare with previous data and get the index where they differ
  index = 1
  if prev_data:
    for index, (first, second) in enumerate(zip(data, prev_data)):
      if first != second:
          break
  prev_data = data
  data = data[index-1:]                    # Remove repeated items
  data = map(lambda x: '"%s"' % x, data)   # Add double quotes
  line = "-> ".join(data) + "\n"           # Generate line with join
  outputfile.write(line)
outputfile.close()

输出文件：

"Subsea Production"-> "Subsea Landing String Services"-> "SenTURIAN E&A Well Test Subsea Landing String Electrohydraulic Operating System"
"Subsea Landing String Services"-> "SenTURIAN Large-Bore Subsea Landing String Electrohydraulic Operating System"
"Subsea Production"-> "Intervention-Constrained & Subsea Applications"-> "MaxFORTE High-Reliability ESP System"
"Intervention-Constrained & Subsea Applications"-> "ZEiTECS Shuttle Rigless ESPReplacement System"
"Subsea Production"-> "OneSubsea, a Schlumberger company"

如何修改输出文件以获取所需的格式

1 个答案: