我正在尝试使用以下数据集汇总一组交易,并选择每个年级的赢家。优胜者是从年级中随机选择的。
{ "_id" : ObjectId("5ce6fb4b3d1be918e574500a"),
"eventId" : ObjectId("5ce2f540bf126322a6be559b"),
"donationAmt" : 32,
"ccTranId" : "HzP4B",
"firstName" : "Jason",
"lastName" : "Jones",
"grade" : "1",
"teacher" : "Smith, Bob",
"studentId" : 100 },
{ "_id" : ObjectId("5ce6fb4b3d1be918e574500b"),
"eventId" : ObjectId("5ce2f540bf126322a6be559b"),
"donationAmt" : 15,
"ccTranId" : "HzP4A",
"firstName" : "Joey",
"lastName" : "Jones",
"grade" : "1",
"teacher" : "Smith, Jane",
"studentId" : 200 },
{ "_id" : ObjectId("5ce6fb4b3d1be918e574500c"),
"eventId" : ObjectId("5ce2f540bf126322a6be559b"),
"donationAmt" : 25,
"ccTranId" : "HzP4D",
"firstName" : "Carrie",
"lastName" : "Jones",
"grade" : "2",
"teacher" : "Smith, Sally",
"studentId" : 300 }
我正在使用此脚本进行汇总。
Donation.aggregate([
{
$match: {
eventId: mongoose.Types.ObjectId(eventId)
}
},
{
"$group": {
"_id": "$studentId",
"first": { "$first": "$firstName" },
"last": { "$first": "$lastName" },
"grade": { "$first": "$grade" },
"teacher": { "$first": "$teacher" }
}
},
{
"$group": {
"_id": "$grade",
"students": {
$push: '$$ROOT'
}
}
}
, { $sort: { _id: 1 } }
])
输出使我可以使用它。然后,我遍历每个元素,并将子文档中的一名学生分配为获胜者。
double group似乎很草率,最好在$ project子句中执行一个表达式以随机分配获胜者。
有没有更清洁的方法?
{
"_id":"1",
"students":[
{
"_id":100,
"first":"Jason",
"last":"Jones",
"grade":"1",
"teacher":"Smith, Bob"
},
{
"_id":200,
"first":"Joey",
"last":"Jones",
"grade":"1",
"teacher":"Smith, Jae"
}
]
},
{
"_id":"2",
students":[ .... ]
},
答案 0 :(得分:1)
随机性意味着您需要获得不可预测的结果。可以在MongoDB中为您提供帮助的唯一操作员是$sample。不幸的是,您无法对数组进行采样。您所能做的就是应用过滤条件,然后对该过滤后的数据集运行{ $sample: { size: 1 } }
:
db.col.aggregate([
{
$match: {
eventId: ObjectId("5ce2f540bf126322a6be559b"),
grade: "2"
}
},
{ $sample: { size: 1 } }
])
要使其更加有用,您可以利用$facet并在一个查询中为每个年级运行多个样本:
db.col.aggregate([
{
$match: {
eventId: ObjectId("5ce2f540bf126322a6be559b")
}
},
{
$facet: {
winner1: [
{ $match: { grade: "1" } },
{ $sample: { size: 1 } }
],
winner2: [
{ $match: { grade: "2" } },
{ $sample: { size: 1 } }
]
// other grades ...
}
}
])