Question

我正在编写一个程序，该程序通过加倍（link to wikihow article）将二进制数转换为十进制数。

如果用户输入的内容不是1或0，则它不是二进制数，在这种情况下，我希望循环“中断”并说出类似的内容：

“糟糕！二进制数字只有1或0”。

如果不“那么”，则循环应继续。

那是我想编码的东西

for(int digits = 0; digits != digitsINbinNum; ++digits){
      if(a condition that checks if user input is anything else than 1 or 0){
         coût << ""Oops! Binary numbers have only 1 or 0" << endl; 
         break;
          }else{
        cin >> binArray[digits];/*<-----------Here's the part where I am trying to do that*/
      }
    }

有关更多信息，请参见下面给出的代码：

#include <iostream>
#include <iterator>

using namespace std;

int main(){
    int digitsINbinNum;
    cout << "If you don't mind. Please enter the number of digits in your binary number: ";
    cin >> digitsINbinNum;
    int binArray[digitsINbinNum];

    cout << "Enter the binary number: ";
    for(int digits = 0; digits != digitsINbinNum; ++digits){
        cin >> binArray[digits];/*<-----------Here's the part where I am trying to do that*/
    }

/*using the doubling method as found in wikihow.com*/
    int total = 0;
    for(int posiOFdigit = 0; posiOFdigit != sizeof(binNum[noOFdigits]); posiOFdigit++){
        total = total * 2 + binNum[posiOFdigit];
    }

    /*Printing the number*/
    cout << "Decimal form of ";
    for(int n = 0; n != noOFdigits; n++){
        cout << binNum[n];
    }
    cout << " is " << total;
    return 0;
}

Answer 1

可以通过问题中给定的link引用通过加倍方法将二进制数转换为十进制数的逻辑。

修改给定代码以使其尽可能接近问题的参考代码。

注意：由于ISO C ++禁止使用可变长度数组，因此我正在更改 int binArray[digits]至 int *binArray = (int *)malloc(sizeof(int) * digitsINbinNum);。此修改使其成为整数指针，并在运行时获取所需大小的内存。

#include <iostream>

using namespace std;

int main(){
    int digitsINbinNum,
        /* variable to keep decimal conversion of given binary */
        decimal_val = 0;
    bool is_binary = true;
    cout << "If you don't mind. Please enter the number of digits in your binary number: ";
    cin >> digitsINbinNum;
    /*
     ISO C++ forbids variable length array,
     making it int pointer and allocating dynamic memory
    */
    int *binArray = (int *)malloc(sizeof(int) * digitsINbinNum);
    if (binArray == NULL)
    {
        cout << "Memory allocation failure" << endl;
        exit -1;
    }
    cout << "Enter the binary number: ";
    for(int digits = 0; digits != digitsINbinNum; ++digits){
        cin >> binArray[digits];
        /*<-----------Here's the part where I am trying to do that*/
        /* doubling method logic for conversion of given binary to decimal */
        if ((binArray[digits] == 0) ||
            (binArray[digits] == 1))
        {
            decimal_val = (decimal_val * 2) + binArray[digits];
        }
        else /* not a binary number */
        {
            is_binary = false;
            cout << "Oops! Binary numbers have only 1 or 0" << endl;
            break;
        }
    }

    /* if conversion is successful: print result */
    if (is_binary)
    {   
        cout << "Decimal Value for given binary is: " << decimal_val << endl;
    }
    if (binArray)
    {
        free(binArray);
    }
    return 0;
}

Answer 2

您不需要为此的数组。这是一个简单的解决方案：

getOpenStatus = (restaurant: _Restaurant) => {
    const closeHour = moment(restaurant.close_at, "HH:mm A").hours();
    const closeMin = moment(restaurant.close_at, "HH:mm A").minutes();
    const openHour = moment(restaurant.open_at, "HH:mm A").hours();
    const openMin = moment(restaurant.open_at, "HH:mm A").minutes();
    const closeMoment = moment({ hours: closeHour, minutes: closeMin });
    const openMoment = moment({ hours: openHour, minutes: openMin });

    if (closeMoment.isBefore(openMoment)) {
        if (moment().isAfter(closeMoment)) closeMoment.add(1, "days");
        else openMoment.subtract(1, "days");
    }

    return moment().isAfter(openMoment) && moment().isBefore(closeMoment);
}

如何获取数组中的特定用户输入？

2 个答案: