我需要实施我的工作四阶Runge-Kutta方法来解决牛顿冷却定律,需要帮助。由于引入了问题的时间(t),因此我对给定条件的排名感到困惑。给出的结果是:时间间隔从t = 0到t = 20(以秒为单位)开始,对象温度= 300,环境温度= 70,时间增量为.1,比例常数为0.19
public class RungeKutta {
public static double functionXnYn(double x,double y)
{
return y-x;
}
public static void main(String[] args) {
double deltaX = (1.005 - 0)/10000;
double y = 10.0;
double result = 0.0;
for(double x = 1.0; x <= 1.005; x = x + deltaX)
{
double k1 = deltaX * functionXnYn(x,y);
double k2 = deltaX * functionXnYn(x + (deltaX/2.0),y + (k1/2.0));
double k3 = deltaX * functionXnYn(x + (deltaX/2.0), y + (k2/2.0));
double k4 = deltaX * functionXnYn(x + deltaX, y + k3);
y = y + (1.0/6.0) * (k1 + (2.0 * k2) + (2.0 * k3) + k4);
result = y;
}
System.out.println("The value of y(1.005) is: " + result);
}
}
贝洛是我的RK4解决ODE的方法。在下面的代码中,假设y(1)= 10且delta x = 0.001,我求解ODE y'= y-x近似y(1.005)
[Symfony\Component\Debug\Exception\FatalThrowableError]
Call to a member function prepare() on null
Exception trace:
() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Connection.php:326
Illuminate\Database\Connection->Illuminate\Database\{closure}() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Connection.php:657
Illuminate\Database\Connection->runQueryCallback() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Connection.php:624
Illuminate\Database\Connection->run() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Connection.php:333
Illuminate\Database\Connection->select() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Connection.php:304
Illuminate\Database\Connection->selectFromWriteConnection() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Schema/Builder.php:75
Illuminate\Database\Schema\Builder->hasTable() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Migrations/DatabaseMigrationRepository.php:169
Illuminate\Database\Migrations\DatabaseMigrationRepository->repositoryExists() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Migrations/Migrator.php:583
Illuminate\Database\Migrations\Migrator->repositoryExists() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Console/Migrations/MigrateCommand.php:91
Illuminate\Database\Console\Migrations\MigrateCommand->prepareDatabase() at /home/masoud/Codes/TheSite/api/vendor/illuminate/database/Console/Migrations/MigrateCommand.php:63
Illuminate\Database\Console\Migrations\MigrateCommand->handle() at n/a:n/a
call_user_func_array() at /home/masoud/Codes/TheSite/api/vendor/illuminate/container/BoundMethod.php:32
Illuminate\Container\BoundMethod::Illuminate\Container\{closure}() at /home/masoud/Codes/TheSite/api/vendor/illuminate/container/BoundMethod.php:90
Illuminate\Container\BoundMethod::callBoundMethod() at /home/masoud/Codes/TheSite/api/vendor/illuminate/container/BoundMethod.php:34
Illuminate\Container\BoundMethod::call() at /home/masoud/Codes/TheSite/api/vendor/illuminate/container/Container.php:576
Illuminate\Container\Container->call() at /home/masoud/Codes/TheSite/api/vendor/illuminate/console/Command.php:183
Illuminate\Console\Command->execute() at /home/masoud/Codes/TheSite/api/vendor/symfony/console/Command/Command.php:255
Symfony\Component\Console\Command\Command->run() at /home/masoud/Codes/TheSite/api/vendor/illuminate/console/Command.php:170
Illuminate\Console\Command->run() at /home/masoud/Codes/TheSite/api/vendor/symfony/console/Application.php:921
Symfony\Component\Console\Application->doRunCommand() at /home/masoud/Codes/TheSite/api/vendor/symfony/console/Application.php:273
Symfony\Component\Console\Application->doRun() at /home/masoud/Codes/TheSite/api/vendor/symfony/console/Application.php:149
Symfony\Component\Console\Application->run() at /home/masoud/Codes/TheSite/api/vendor/illuminate/console/Application.php:90
Illuminate\Console\Application->run() at /home/masoud/Codes/TheSite/api/vendor/laravel/lumen-framework/src/Console/Kernel.php:115
Laravel\Lumen\Console\Kernel->handle() at /home/masoud/Codes/TheSite/api/artisan:35
基于公式T(t)= Ts +(T0-Ts)* e ^(-k * t),对于牛顿DE求解,我应该具有75.1的近似值。 Ts =环境温度,T0 =对象初始温度,t = 20(经过的秒数),k = .19比例常数
答案 0 :(得分:0)
我猜测(但不是很难)您要解决的ODE是
dT(t)/dt = -k*(T(t)-T_amb)
如您所见,右侧并不直接取决于时间。
当您不尝试为系统编码时,环境温度T_amb
可能是一个常数。因此,在常量周围移动并使用一致的函数名称,然后将ODE函数参数返回为格式time, state variable
public class RungeKutta {
public static double CoolingLaw(double time, double objectTemp)
{
double k = 0.19, ambientTemp = 70.0;
return -k * (objectTemp - ambientTemp);
}
public static void main(String[] args) {
double result = 0.0;
double objectTemp = 300.0;
double dt = 0.1
for(double t = 0.0; t <= 20.0; t += dt)
{
double k1 = dt * CoolingLaw(t, objectTemp);
double k2 = dt * CoolingLaw(t + (dt/2.0), objectTemp + (k1/2.0));
double k3 = dt * CoolingLaw(t + (dt/2.0), objectTemp + (k2/2.0));
double k4 = dt * CoolingLaw(t + dt, objectTemp + k3);
objectTemp = objectTemp + (1.0/6.0) * (k1 + (2.0 * k2) + (2.0 * k3) + k4);
result = objectTemp;
}
System.out.println("The approx. object temp after 20 seconds is: " + result);
}
}