Question

代码：

$data = array("vanilla", "strawberry", "mango", "peaches");
print_r(array_slice($data, 1, 2));


Output:
Array
(
[0] => strawberry
[1] => mango
)

就我而言：

$data = array("vanilla", "strawberry", "mango", "peaches");
$sub_set_data = array( "strawberry", "mango");

输出将是保留数组： array("vanilla", "peaches");

编辑：

NOT array diff it look like the minus operator 7-3 = 4 or $C = $A-$B

python概念：

>>> A           = [6, 7, 8, 9, 10, 11, 12]
>>> subset_of_A  = [6, 9, 12];
>>> set(A) - set(subset_of_A)
set([8, 10, 11, 7])
>>>

我如何处理此案？

Answer 1

您似乎需要array_diff

<?php
$array1 = array("a" => "green", "red", "blue", "red");
$array2 = array("b" => "green", "yellow", "red");
$result = array_diff($array1, $array2);

print_r($result);
?>

结果：

Array
(
    [1] => blue
)

http://www.php.net/manual/en/function.array-diff.php

数组切片（$ data，1,2）我的情况是等价的？

1 个答案: