I'm trying to solve a multi-objective problem in which I have to minimize two different objectives but with one taking priority over the other one.
To solve the problem, and hence the question, I tried to use weighted sum of both objective functions. The problem here is that that approach finds the minimum value between the two problems which I don't want. I want to solve one objective and then, maintaning that specific value, I want to solve the other problem.
答案 0 :(得分:1)
CPLEX的12.9版可以完全做到这一点:解决一个目标,确定其价值,然后转移到下一个目标。这是一个示例LP:
Maximize multi-objectives
first: abstol=2
x1
second: priority=-1
x2
Subject to
x1 + x2 = 10
General
x1 x2
End
the release notes和these slides中都描述了此功能。
答案 1 :(得分:1)
您可以使用staticLex。
int nbKids=200;
float costBus40=500;
float costBus30=400;
float costBus50=625;
dvar int+ nbBus40;
dvar int+ nbBus30;
dvar int+ nbBus50;
dvar float cost;
dvar float co2emission;
minimize
staticLex(cost,co2emission);
subject to
{
cost==costBus40*nbBus40 +nbBus30*costBus30+nbBus50*costBus50;
co2emission==nbBus50+nbBus40*1.1+nbBus30*1.2;
40*nbBus40+nbBus30*30+nbBus50*50>=nbKids;
}
execute DISPLAY_After_SOLVE
{
writeln("The minimum cost is ",cost);
writeln("CO2 emission is ",co2emission);
writeln("We will use ",nbBus40," 40 seats buses ",nbBus30,
" 30 seats buses and ", nbBus50," buses 50 seats");
}
给出
The minimum cost is 2500
CO2 emission is 4
We will use 0 40 seats buses 0 30 seats buses and 4 buses 50 seats
我5天前发布了此答案,但被主持人删除了。
上的一个小例子答案 2 :(得分:0)