Question

我想在一张图中绘制3种不同的占用模式：a。当男性和女性都在工作时； b。）只有男性在工作； c。）只有女性在工作。

我使用facet创建了3个不同的data.frames

第一个数据帧（男性和女性都在工作）的结构是：

   structure(list(time = c("04:00", "04:15", "04:30", "04:45", "05:00", 
"05:15", "05:30", "05:45", "06:00", "06:15", "06:30", "06:45", 
"07:00", "07:15", "07:30", "07:45", "08:00", "08:15", "08:30", 
"08:45", "09:00", "09:15", "09:30", "09:45", "10:00", "10:15", 
"10:30", "10:45", "11:00", "11:15"), day = c("Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday"
), variable = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L), .Label = c("Shifts on Monday", "Shifts on Tuesday", 
"Shifts on Wednesday", "Shifts on Thursday", "Shifts on Friday", 
"Shifts on Saturday", "Shifts on Sunday"), class = "factor"), 
    value = c(102, 110, 116, 120, 148, 152, 188, 204, 318, 348, 
    418, 442, 752, 816, 1064, 1144, 1836, 1942, 2402, 2524, 3240, 
    3324, 3486, 3520, 3594, 3592, 3596, 3568, 3594, 3626), size_f = structure(c(1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("Monday", 
    "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", 
    "Sunday"), class = "factor")), row.names = c(NA, 30L), class = "data.frame")

第二个data.frame（男性正在工作）的结构是：

dput(head(melted_WkSTiWeekM , 30))
structure(list(time = c("04:00", "04:15", "04:30", "04:45", "05:00", 
"05:15", "05:30", "05:45", "06:00", "06:15", "06:30", "06:45", 
"07:00", "07:15", "07:30", "07:45", "08:00", "08:15", "08:30", 
"08:45", "09:00", "09:15", "09:30", "09:45", "10:00", "10:15", 
"10:30", "10:45", "11:00", "11:15"), day = c("Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday"
), variable = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L), .Label = c("Shifts on Monday", "Shifts on Tuesday", 
"Shifts on Wednesday", "Shifts on Thursday", "Shifts on Friday", 
"Shifts on Saturday", "Shifts on Sunday"), class = "factor"), 
    value = c(56, 58, 64, 68, 84, 84, 104, 114, 172, 196, 224, 
    238, 410, 442, 560, 604, 930, 968, 1188, 1230, 1576, 1620, 
    1692, 1706, 1740, 1746, 1752, 1740, 1736, 1756), size_f = structure(c(1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("Monday", 
    "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", 
    "Sunday"), class = "factor")), row.names = c(NA, 30L), class = "data.frame")

第二个data.frame（女性正在工作）的结构是：

structure(list(time = c("04:00", "04:15", "04:30", "04:45", "05:00", 
"05:15", "05:30", "05:45", "06:00", "06:15", "06:30", "06:45", 
"07:00", "07:15", "07:30", "07:45", "08:00", "08:15", "08:30", 
"08:45", "09:00", "09:15", "09:30", "09:45", "10:00", "10:15", 
"10:30", "10:45", "11:00", "11:15"), day = c("Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday", 
"Monday", "Monday", "Monday", "Monday", "Monday", "Monday", "Monday"
), variable = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
1L, 1L, 1L, 1L, 1L), .Label = c("Shifts on Monday", "Shifts on Tuesday", 
"Shifts on Wednesday", "Shifts on Thursday", "Shifts on Friday", 
"Shifts on Saturday", "Shifts on Sunday"), class = "factor"), 
    value = c(46, 52, 52, 52, 64, 68, 84, 90, 146, 152, 194, 
    204, 342, 374, 504, 540, 906, 974, 1214, 1294, 1664, 1704, 
    1794, 1814, 1854, 1846, 1844, 1828, 1858, 1870), size_f = structure(c(1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 
    1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("Monday", 
    "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", 
    "Sunday"), class = "factor")), row.names = c(NA, 30L), class = "data.frame")

此后，我创建了一个

melted_WkSTiWeekAll=cbind(melted_WkSTiWeek,melted_WkSTiWeekM,melted_WkSTiWeekF)



structure(list(time = c("04:00", "04:15", "04:30", "04:45", "05:00"
), day = c("Monday", "Monday", "Monday", "Monday", "Monday"), 
    variable = structure(c(1L, 1L, 1L, 1L, 1L), .Label = c("Shifts on Monday", 
    "Shifts on Tuesday", "Shifts on Wednesday", "Shifts on Thursday", 
    "Shifts on Friday", "Shifts on Saturday", "Shifts on Sunday"
    ), class = "factor"), value = c(102, 110, 116, 120, 148), 
    size_f = structure(c(1L, 1L, 1L, 1L, 1L), .Label = c("Monday", 
    "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", 
    "Sunday"), class = "factor"), time = c("04:00", "04:15", 
    "04:30", "04:45", "05:00"), day = c("Monday", "Monday", "Monday", 
    "Monday", "Monday"), variable = structure(c(1L, 1L, 1L, 1L, 
    1L), .Label = c("Shifts on Monday", "Shifts on Tuesday", 
    "Shifts on Wednesday", "Shifts on Thursday", "Shifts on Friday", 
    "Shifts on Saturday", "Shifts on Sunday"), class = "factor"), 
    value = c(56, 58, 64, 68, 84), size_f = structure(c(1L, 1L, 
    1L, 1L, 1L), .Label = c("Monday", "Tuesday", "Wednesday", 
    "Thursday", "Friday", "Saturday", "Sunday"), class = "factor"), 
    time = c("04:00", "04:15", "04:30", "04:45", "05:00"), day = c("Monday", 
    "Monday", "Monday", "Monday", "Monday"), variable = structure(c(1L, 
    1L, 1L, 1L, 1L), .Label = c("Shifts on Monday", "Shifts on Tuesday", 
    "Shifts on Wednesday", "Shifts on Thursday", "Shifts on Friday", 
    "Shifts on Saturday", "Shifts on Sunday"), class = "factor"), 
    value = c(46, 52, 52, 52, 64), size_f = structure(c(1L, 1L, 
    1L, 1L, 1L), .Label = c("Monday", "Tuesday", "Wednesday", 
    "Thursday", "Friday", "Saturday", "Sunday"), class = "factor")), row.names = c(NA, 
5L), class = "data.frame")

变量time, day, variable and size_f相似。

我想在同一张图中一起绘制3张图。但是我不知道如何做到这一点

在下面的图中使用建议的facet

情节1

情节2

情节3

如何前进

我想创建一个像这样的锅

Answer 1

您可以执行此操作，但是将数据框合并在一起，并分别将其标记为All，Male和Female。然后，您可以在ggplot函数中使用该标签进行分组（着色）。

使用geom_bar和position = "identity"，您会在每个广告的上方看到条形图，以消除条形图之间的间隔（以模仿密度图的外观）width设置为{{1 }}。 1可用于更改alpha颜色的透明度。

要获取一周中每一天的单独图表，请使用fill。

facet_wrap(~day)

^{请注意，由于提供的数据仅包含星期一的条目，因此在这里我们只得到一个library(tidyverse)

melted_WkSTiWeekAll <- bind_rows(list(All=melted_WkSTiWeek,
Male=melted_WkSTiWeekM,
Female=melted_WkSTiWeekF),
.id = 'source')

ggplot(melted_WkSTiWeekAll, aes(x=time, y=value, fill=source)) +
geom_bar(stat="identity", position = "identity", alpha=.3, width=1) +
facet_wrap(~day)
。} ^{由reprex package（v0.3.0）于2019-05-31创建}

如何叠加多个图

1 个答案: