Question

我有以下数据

{"array": [[1288.1639933233453], [1255.1777295971826], 
[1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}

我想按如下方式转换上述数据

[{"value": 1288.1639933233453},
{"value": 1255.1777295971826},
{"value": 1250.1075681742996},
{"value": 1283.9962801780075},
{"value": 1297.4411412000093}]

Answer 1

d = {"array": [[1288.1639933233453], [1255.1777295971826],
               [1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}
d = [{"value": i[0]} for i in d["array"]]
print(d)

输出：

[{'value': 1288.1639933233453}, {'value': 1255.1777295971826}, {'value': 1250.1075681742996}, {'value': 1283.9962801780075}, {'value': 1297.4411412000093}]

Answer 2

x = {"array": [[1288.1639933233453], [1255.1777295971826], 
[1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}
y = [{'value' : i[0]} for i in x['array']]
print(y)

Answer 3

d1 = {"array": [[1288.1639933233453], [1255.1777295971826], [1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}
vals = d1["array"]
l = []
for val in vals:
    l.append({"value": val[0]})
print(l)

[{'value': 1288.1639933233453},
 {'value': 1255.1777295971826},
 {'value': 1250.1075681742996},
 {'value': 1283.9962801780075},
 {'value': 1297.4411412000093}]

Answer 4

使用lambda

a={"array": [[1288.1639933233453], [1255.1777295971826], 
[1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}

res = list(map(lambda x:{'value':x[0]},a['array']))

Answer 5

您没有提到列表包含列表将始终包含1个元素，因此，我认为最好遍历所有列表包含列表理解而不遗漏值：

d = {"array": [[1288.1639933233453], [1255.1777295971826], [1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}

r = [{"value": v} for e in d["array"] for v in e]

输出：

[{'value': 1288.1639933233453}, {'value': 1255.1777295971826}, {'value': 1250.1075681742996}, {'value': 1283.9962801780075}, {'value': 1297.4411412000093}]

Answer 6

您可以使用以下代码：

myDic = {"array": [[1288.1639933233453], [1255.1777295971826], 
[1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}

myList = []

for i in myDic['array']:
    value = {'value':i[0]}
    myList.append(value)

print(myList)

OR

使用pythonic方法：）

myDic = {"array": [[1288.1639933233453], [1255.1777295971826], 
[1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}

myList = [{'value':i[0]} for i in myDic['array']]

print(myList)

Answer 7

您可以这样做：

values = {"array": [[1288.1639933233453], [1255.1777295971826], 
[1250.1075681742996], [1283.9962801780075], [1297.4411412000093]]}

values = [{"value: i[0]} for i in values["array"]]

将列表数组转换为字典数组

7 个答案:

OR