我想问用户是否要播放“ [y | n]”，但是我的输入验证不起作用。我一直在为此绞尽脑汁，但似乎缺少一些基本知识。
代码正在读取值，但没有像我期望的那样通过布尔表达式。输入“ y”将显示“请输入'y'或'n'以继续：”
与链接推断的重复问题不同，我想对此控件使用WHILE循环，以允许多个错误的用户输入。
NB;游戏循环控制仅在验证用户[y | n]输入时出现问题。
printf("Would you like to play dice poker? y/n: ");
scanf(" %c", &play);
while (play == 'y'|| play== 'Y' || play == 'n' || play == 'N') {
while (play != 'y'|| play != 'Y' || play != 'n' || play != 'N') {
printf("input must be [y|n]\n");
printf("please enter a 'y' or 'n' to continue:");
scanf(" %c", &play);
}
/*if/else loop to play or farewell and exit*/
/*Game Code - Works just fine*/
printf("Would you like to play again? [y|n] : ");
scanf(" %c", &playAgain);
while (playAgain != 'y' || playAgain != 'Y' || playAgain = 'n' || playAgain != 'N') {
printf("input must be [y|n]\n");
printf("please enter a 'y' or 'n' to continue:");
scanf(" %c", &playAgain);
}
play = 'x'; //kick out of "play" loop
}