Question

我在我的第一个学期的java和我的阅读障碍使得这个更加困难，但我坚持。我需要获取用户输入的行数，字符数和字符类型。这是为了hw，所以任何建议都表示赞赏。我需要使用一个方法（调用）来创建一个带有相应输入变量的模式，并打印总字符数：

行数：3
字符数：6
字符：X

XXXXXX
XXXXXX
XXXXXX

总人物：18
这是我到目前为止的代码：

static Scanner console = new Scanner(System.in);  
  public static void main (String[] args)  
  {  
    int totalChar;  
    int numLn = console.nextInt();          //Should I assign here or  
    int charPerLn = console.nextInt();      //after sys.println?  
    char symbol = console.next().charAt(0);  

    System.out.println("# of lines: " +numLn);

    System.out.println("# of characters: "+charPerLn);

    System.out.println("Character: "+symbol);

    System.out.print(Pattern);    //Pretty sure this is wrong or at
                                  //least in the wrong place to call

    System.out.println("Total Characters: "+totalChar);
    totalChar = numOfLines * charPerLine;
}

public static int Pattern(int x)
{
    int pattern;

    //I need a nested while or for loop here but I'm not sure how to 
    //assign the main's values for #lines and #character
    //Am I over-thinking this?  

    return pattern;
}

Answer 1

Pattern方法应类似于以下内容：

public static int Pattern(int lineCount, int charCount, char character) {

    for (int i = 0; i < lineCount; i++) {
        // Repeat the supplied character for charCount
    }
}

Pattern方法现在包含行数和每行字符数的参数，因为这些值将决定迭代的次数。我将保留每行正确打印字符数的逻辑（这将给出整个答案），但循环（索引i）遍历行数。通常，当您想要重复某些n次时，您创建一个具有以下基本结构的循环：

for (i = 0; i < n; i++) { /* ... */ }

这意味着在第一次迭代时，i等于0，然后是1，然后是2，依此类推，直到i到达{{1} }}。此时，迭代停止。这导致迭代n-1次，其中n取值为i。

问题的其余部分可以通过再次应用同样的原则来解决。

Answer 2

static Scanner console = new Scanner(System.in);  
public static void main (String[] args)  
{  
    int totalChar;  
    int numOfLines = console.nextInt(); 
    int charPerLine = console.nextInt(); // keep your variable names consistent by using either "charPerLn" or "charPerLine", not both :)
    char symbol = console.next().charAt(0);  

    System.out.println("# of lines: " + numOfLines);
    System.out.println("# of characters: " + charPerLine);
    System.out.println("Character: " + symbol);
    System.out.println(getPattern( /* [use, the, parameters, from, above, here] */ ));

    totalChar = numOfLines * charPerLine; // first assign to totalChar, then you can print it
    System.out.println("Total Characters: " + totalChar);
}

public static String getPattern(int numOfLines, int charPerLine, char symbol) // you want to return a string, so we change "int" to "String" here
{
    String pattern = "";

    /* As "that other guy" said, nested for loops go here */
    for(/* ... */)
    {
        /* ... */
        for(/* ... */)
        {
         /* ... */
        }
        /* ... */
    }

    return pattern;
}

Java方法字符模式 - 初学者

2 个答案: