Question

这是一个简单的体重转换程序。目的是将EnglishWeight1除以5磅12盎司的数字。我使用try-throw-catch方法处理除以0的问题。

请帮助。

//Class Declaration
class EnglishWeight
{
    private:
        int pounds, ounces;
    public:
        EnglishWeight(void); //0-argument constructor
        EnglishWeight(int lbs, int oz);
        EnglishWeight ScalarDivision(const int &s, int *check) const; 
};

//Member Function Definition
EnglishWeight::EnglishWeight(void)
{
    pounds = ounces = 0;
}
EnglishWeight::EnglishWeight(int lbs, int oz)
{
    pounds = lbs;
    ounces = oz;
}

EnglishWeight EnglishWeight::ScalarDivision(const int &s, int *check) const //Scalar Division function
{
    EnglishWeight sdivide; //Declare variable 
    try
    {
        if (s == 0) //DIV/0 check
            throw 0;
        else
        {
            sdivide.ounces = (pounds * 16) + ounces;
            sdivide.pounds = sdivide.ounces / (16 * s);
            sdivide.ounces = sdivide.ounces % 16;
            return sdivide;
        }
    }
    catch (int x)
    {
        *check = x;
    }
}

void EnglishWeight::Show() const
{
    std::cout << pounds << " pounds, " << ounces << " ounces";
}

//Main Driver
int main(void)
{
    EnglishWeight EnglishWeight1(5, 12);
    EnglishWeight sdiv1;
    int number = 0;
    int flag = 1;

        sdiv1 = EnglishWeight1.ScalarDivision(number, &flag);
    if (flag == 0)
        std::cout << "EnglishWeight1 / number = DIV/0" << std::endl;
    else
    {
        std::cout << "EnglishWeight1 / number = ";
        sdiv1.Show();
        std::cout << std::endl;
    }
}

错误：0xC0000005：访问冲突读取位置0x0000000000000000，这可能意味着编译器正在某处读取垃圾值。我只是不知道如何解决。

Answer 1

@WhozCraig建议工作。谢谢！

“在发生div-0异常的情况下，没有指定任何返回值。因此，您基本上是对EnglishWeight1.ScalarDivision的调用者说谎，声称您将在所有代码路径上返回EnglishWeight。坦率地说，我不能理解您的编译器如何未发出有关“并非所有代码路径都提供返回值”或类似措辞的警告。

“仅按原样返回sdivide。无论如何，您的呼叫者都不会使用它”

添加DIV / 0异常处理。我做错了事，但无法指出问题所在

1 个答案: