Question

由于明天我要去上课，请帮忙。我的职责是“创建一个程序，从皇后所在的字段中确定皇后可用的棋盘区域。棋盘以8x8矩阵表示。皇后的位置从键盘输入[字母] [数字]。并将结果保存在字符串中。“

我有点坚持如何继续，我想我需要像8种不同的if。 2为水平，2为垂直和4为对角线，但我不知道该怎么做。

int main()
{

    int horizontal,vertical,i,j,current;
    char poz;

    printf("Enter the horizontal position of queen(A-H)\n");
    scanf("%s", &poz);

    if(poz=='A')
    {
        horizontal=1;
    }
    else if (poz=='B')
    {
        horizontal=2;
    }   
    else if (poz=='C')
    {
        horizontal=3;
    }
    else if (poz=='D')
    {
        horizontal=4;
    }   
    else if (poz=='E')
    {
        horizontal=5;
    }
    else if (poz=='F')
    {
        horizontal=6;
    }
    else if (poz=='G')
    {
        horizontal=7;
    }
    else if (poz=='H')
    {
        horizontal=8;
    }

    printf("Enter the vertical position of queen(1-8)\n");
    scanf("%d",&vertical);

    int n=8,m=8;

    int chess[8][8]={
    {1,2,3,4,5,6,7,8},
    {1,2,3,4,5,6,7,8},
    {1,2,3,4,5,6,7,8},
    {1,2,3,4,5,6,7,8},
    {1,2,3,4,5,6,7,8},
    {1,2,3,4,5,6,7,8},
    {1,2,3,4,5,6,7,8},
    {1,2,3,4,5,6,7,8},
    };

    printf("Queen pos is %c-%d",poz,vertical );


return 0;
}

Answer 1

强烈建议将水平位置和垂直位置的索引都修改为0 ... 7，然后包括：（其中“ r”是行，“ c”是列）

All positions in the column (0..7)/(c) where the queen is placed except (r)/(c) 

All positions in the row (r)/(0..7) where the queen is placed except (r)/(c)

然后从皇后位置（r）/（c）开始

all successive positions (r+1)/(c-1) until edge of board
all successive positions (r+1)/(c+1) until edge of board
all successive positions (r-1)/(c-1) until edge of board
all successive positions (r-1)/(c+1) until edge of board

以上是一些'for（）'语句，应该相对容易实现。

作业问题，国际象棋皇后可用字段

1 个答案: