Question

我有此日志文件，并且我试图避免打印包含模式“ APLHA”的文本。

   +++ skdfhahjsahsdjk >
** ALPHA EDFJDJFKLJDKFJKSDLFJL
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

   +++ skdfhahjsahsdjk >
* KJENRFKES DFJKLSDFJEDFJDJFKLJDKFJKSDLFJL
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

   +++ skdfhahjsahsdjk >
CL mesukww juwaehdiearfa
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

   +++ skdfhahjsahsdjk >
*C KJENRFKESDFJ ksludhieokdaewmdp
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

 +++ skdfhahjsahsdjk >
** BETA EDFJDJFKLJDKFJKSDLFJL
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

我尝试过这种方式，但没有成功。它会打印出除“ ALPHA”外的其余文本

cat日志文件| grep -v“ ALPHA”
结果：

+++ skdfhahjsahsdjk >
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

我期望未打印包含“ ALPHA”的整个日志，如下所示：

 +++ skdfhahjsahsdjk >
* KJENRFKES DFJKLSDFJEDFJDJFKLJDKFJKSDLFJL
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

   +++ skdfhahjsahsdjk >
CL mesukww juwaehdiearfa
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

   +++ skdfhahjsahsdjk >
*C KJENRFKESDFJ ksludhieokdaewmdp
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

 +++ skdfhahjsahsdjk >
** BETA EDFJDJFKLJDKFJKSDLFJL
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

对于这种情况，您能否提出其他解决方案的建议？

关于Dom

Answer 1

尝试一下：

awk 'BEGIN{RS=ORS="\n\n"}!/ALPHA/' file

Answer 2

使用perl的slurp模式（启用-00）的替代解决方案。这将告诉perl认为段落是一个记录而不是行。以后很清楚，仅当ALPHA不存在时才打印。

perl -00 -ne  'print if  !/ALPHA/' inputfile
   +++ skdfhahjsahsdjk >
* KJENRFKES DFJKLSDFJEDFJDJFKLJDKFJKSDLFJL
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

   +++ skdfhahjsahsdjk >
CL mesukww juwaehdiearfa
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

   +++ skdfhahjsahsdjk >
*C KJENRFKESDFJ ksludhieokdaewmdp
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

 +++ skdfhahjsahsdjk >
** BETA EDFJDJFKLJDKFJKSDLFJL
   SDFSDGDRGRTG
   WEFETTFYRT #168113++-

过滤复杂文件中的特定模式

2 个答案: