Question

所以我正在编码井字游戏

我将环境创建为9个元素的列表，如下所示-

board=[' ']*9

然后我将X或O放在板上

board[move-1] = 'X'

效果很好

我遇到的问题是放置X或O后，我无法检查获胜条件。输出始终返回为假check the output here

if (board[0] and board[1] and board[2] == 'X') or (board[0] and board[1] and board[2] == 'O') :
    return winner==1

即使在索引0,1和2为X的情况下，上述代码中的

也会将获胜者返回为false。

我认为这是一个简单的字符串处理问题，但我不确定。任何帮助将不胜感激。

Answer 1

尝试对if语句使用以下内容：如果all的所有3个元素均为True，则board将为X。 O

也是如此

if all(board[i]=='X' for i in range(3)) or all(board[i]=='O' for i in range(3)):
    return winner==1

Answer 2

要涵盖垂直，水平和对角线，您可以建立每个方向的轴位置列表，并检查是否有任何一个映射到XXX或OOO：

axes = [(0,1,2),(3,4,5),(6,7,8),(0,3,6),(1,4,7),(2,5,8),(0,4,8),(2,4,6)]
win = any(board[a]+board[b]+board[c] in ["XXX","OOO"] for a,b,c in axes)

如果要让计算机玩游戏，可以创建一个移动评级功能，该功能可以分析每个可玩位置并返回与该位置的好坏相对应的数字。

这是一个例子：

from random import sample
axes = [(0,1,2),(3,4,5),(6,7,8),(0,3,6),(1,4,7),(2,5,8),(0,4,8),(2,4,6)] 

def isWin(board):
    return any(board[a]+board[b]+board[c] in ["XXX","OOO"] for a,b,c in axes)

def rating(position,play,board,level=3**6):
    if board[position] != " " or level < 3: return 0
    newBoard = board[:position]+[play]+board[position+1:]
    if isWin(newBoard): return level*2
    nextRatings = [rating(p,"XO"[play=="X"],newBoard,level/3) for p in range(9)]
    return level-max(nextRatings,key=abs)

while True:
    board = [" "]*9
    player,computer = sample("XOXO",2)
    while True:
        for r in range(0,9,3):
            print("("+") (".join(board[r:r+3])+")",list(range(r+1,r+4)))
        available = [str(p+1) for p in range(9) if board[p] == " "]
        if isWin(board) or not available : break
        player = "XO"[player=="X"]
        if player == computer:           
            position = max(sample(range(9),9),key=lambda p:rating(p,computer,board))
            print(f"Computer plays {player} at {position+1}")
        else:
            while True:
                position = input(f"Position to play for {player}: ")
                if position not in available: print("Invalid position")
                else : position = int(position)-1; break
        board[position] = player
    print( f"{player}'s WIN !!!\n" if isWin(board) else "DRAW.\n")

rating()函数通过可能的移动来递归地返回一个值，该值基于达到游戏结束所需的移动数量而越来越小。每个级别的值根据轮到哪个玩家而增加或减少

如何检查列表的特定元素的字符串值？

2 个答案: