我试图获取术语列表并以特定格式输出它们。
例如,我有一个动词列表:
verbs = ['eat', 'run', 'jump', 'play', 'walk', 'talk', 'send']
我希望我的输出是一个字符串,其中列表中的每个项目也是一个字符串,由|
magic(verbs)
输出:
"eat" | "run" | "jump" | etc.
我尝试过使用.join
方法,但这只是给了我一大串由管道分隔的术语,而不是我想要的。有任何想法吗?我对Python很陌生,如果这是令人难以置信的低眉或其他地方已经回答的话,我很抱歉。
答案 0 :(得分:3)
verbs = ['eat', 'run', 'jump', 'play', 'walk', 'talk', 'send']
x=(' | '.join('"' + item + '"' for item in verbs))
print(x)
你可以看到ouput here
答案 1 :(得分:2)
尝试:
verbs = ['eat', 'run', 'jump', 'play', 'walk', 'talk', 'send']
print("|".join(['"'+e+'"' for e in verbs]))
输出:
"eat"|"run"|"jump"|"play"|"walk"|"talk"|"send"
答案 2 :(得分:2)
这样做你想要的:
def magic(terms):
print(' | '.join('"%s"' % term for term in terms))
verbs = ['eat', 'run', 'jump', 'play', 'walk', 'talk', 'send']
magic(verbs) # -> "eat" | "run" | "jump" | "play" | "walk" | "talk" | "send"
答案 3 :(得分:2)
verbs = ['eat', 'run', 'jump', 'play', 'walk', 'talk', 'send']
def magic(s):
return ' | '.join('"%s"' % x for x in s)
print(magic(verbs))
# "eat" | "run" | "jump" | "play" | "walk" | "talk" | "send"
答案 4 :(得分:0)
在每个引号括起的动词之间,放一个管道:
" | ".join('"{0}"'.format(verb) for verb in verbs)
>>> verbs = ['eat', 'run', 'jump', 'play', 'walk', 'talk', 'send']
>>> print(" | ".join('"{0}"'.format(verb) for verb in verbs))
"eat" | "run" | "jump" | "play" | "walk" | "talk" | "send"