Question

查询：

select column_one, column_two, column_three 
from main_tbl_name

输出：

column_one  column_two
--------------------------------------------------------------------------------
data1       SBANAR SBARTO SCBADP SCCHBA SCHPIT SCTHAB SDPCLV SDPRPN SDPSEC SERIE
data2       SRALEN SRETIN SRUNLI SSAPEL SSATAR SSCMAR SSDECA
data3       DRAP14 E05A E1 ECOMOD ENJO01 ENPC01 ESPHSA ESS

我还有另一个查询：

select column_one, column_two, column_three 
from another_tbl_name 
where column_four in (main_tbl_name.column_two)

我需要将main_tbl_name.column_two的值分成例如（'SBANAR'，'SBARTO'，'SCBADP'，'SCCHBA'，'SCHPIT'，'SCTHAB'，'SDPCLV'，' SDPRPN'，'SDPSEC'，'SERIE'）

在上面的第二个查询中，如果存在某些值，请在main_tbl_name.column_three中附加每个迭代的值

所以我的最终输出应该是

column_one  column_two                                                                  column_three
-------------------------------------------------------------------------------------------------------------------------
data1       SBANAR SBARTO SCBADP SCCHBA SCHPIT SCTHAB SDPCLV SDPRPN SDPSEC SERIE        SBANAR SBARTO SCCHBA SDPCLV SDPSEC
data2       SRALEN SRETIN SRUNLI SSAPEL SSATAR SSCMAR SSDECA                            SRALEN SSCMAR SSDECA
data3       DRAP14 E05A E1 ECOMOD ENJO01 ENPC01 ESPHSA ESS                              DRAP14 E05A ESPHSA ESS

Answer 1

以下是一个与您的数据类似的示例：

with 

-- sample data
  main_tbl_name ( column_one,  column_two) as (
    select 'data1', 'SBANAR SBARTO SCBADP SCCHBA SCHPIT SCTHAB SDPCLV SDPRPN SDPSEC SERIE' 
      from dual union all
    select 'data2', 'SRALEN SRETIN SRUNLI SSAPEL SSATAR SSCMAR SSDECA' 
      from dual union all
    select 'data3', 'DRAP14 E05A E1 ECOMOD ENJO01 ENPC01 ESPHSA ESS' from dual ),
  another_tbl_name(column_four) as (
    select 'SDPSEC SBANAR SBARTO SCCHBA SDPCLV' from dual union all
    select 'DRAP14 E05A ESPHSA ESS' from dual), 
  -- end of sample data

  t1 as (select column_one c1, column_two c2, '"'||replace(column_two, ' ', '", "')||'"' cx 
           from main_tbl_name),
  t2 as (select '"'||replace(column_four, ' ', '", "')||'"' cx 
           from another_tbl_name)
select c1, c2, listagg(b.cs, ' ') within group (order by b.cs) c3
  from (select c1, c2, trim(column_value) cs from t1, xmltable(cx)) a
  left join (select trim(column_value) cs from t2, xmltable(cx)) b on a.cs = b.cs
  group by c1, c2

...结果：

C1    C2                                                                   C3
----- -------------------------------------------------------------------- -------------------------------
data1 SBANAR SBARTO SCBADP SCCHBA SCHPIT SCTHAB SDPCLV SDPRPN SDPSEC SERIE SBANAR SBARTO SCCHBA SDPCLV SDPSEC
data2 SRALEN SRETIN SRUNLI SSAPEL SSATAR SSCMAR SSDECA
data3 DRAP14 E05A E1 ECOMOD ENJO01 ENPC01 ESPHSA ESS                       DRAP14 E05A ESPHSA ESS

^demo

此解决方案基于xmltable，左联接和listagg()。我假设单个空格是分隔符。如果another_table包含的数据不是列表形式，那么您甚至可以简化此查询。

基本上，您必须拆分 list 列，然后进行联接。还有其他方法可以执行此操作，例如分层查询，已经发布在SO上的PLSQL函数。使用适合您的任何方法。

Answer 2

所以你想：

将main_tbl_name.column_two转换为行
对于每个生成的行，链接到现有表行之一？

如果是这样，您可以执行以下操作：

WITH DATA AS
     ( SELECT 44 AS COLUMN_ONE  ,'WORD1 WORD2 WORD3 <!-- language: lang-sql --> WORD4 WORD5 WORD6' COLUMN_TWO FROM DUAL     )
SELECT COLUMN_ONE  ,TRIM(REGEXP_SUBSTR(COLUMN_TWO, <!-- language: lang-sql --> '[^ ]+', 1, LEVEL)) COLUMN_TWO
FROM DATA
CONNECT BY INSTR(COLUMN_TWO, ' ', 1, LEVEL - 1) > 0;

COLUMN_ONE  COLUMN_TWO
44          WORD1
44          WORD2
44          WORD3
44          WORD4
44          WORD5
44          WORD6

干杯！！！迪伦

如何通过使用oracle迭代列的行值来在选择列名称中使用选择查询？

2 个答案: