Question

我有一张表，每个条目都有一个计数器对

Customer
   Name                Value
   Bob                 3
   Bob                 4
   Sam                 0
   Sam                 1
   Joe                 9

我想要以下结果

Customer
   Name                Value1          Value2
   Bob                 3               4
   Sam                 0               1
   Joe                 9

我已经阅读了这个帖子Oracle query to put rows at odd number adjacent to even number，但是我想避免使用MOD函数而不是使用pivot。

Answer 1

如果每个名称只有两个值，则不能在此处使用pivot语句（它也适用于日期，因为我们可以使用日期的最大值和分钟数）：

select name, min(value) value1, nullif(max(value), min(value)) value2
  from customer_tables
 group by name

如果Bob，Sam和其他人有更多这两个值：

with t (Name, Value) as (
select 'Bob',3 from dual union all
select 'Bob',4 from dual union all
select 'Sam',0 from dual union all
select 'Sam',1 from dual union all
select 'Joe',9 from dual 
), t1 (name, value, rn) as (
select name, value, ROW_NUMBER() OVER(partition by name order by value) from t
)
select * from t1
pivot XML (
  max(value) 
  for rn in (ANY)
)

SQL> l
  1  with t (Name, Value) as (
  2  select 'Bob',3 from dual union all
  3  select 'Bob',4 from dual union all
  4  select 'Sam',0 from dual union all
  5  select 'Sam',1 from dual union all
  6  select 'Joe',9 from dual
  7  ), t1 (name, value, rn) as (
  8  select name, value, ROW_NUMBER() OVER(partition by name order by value) from t
  9  )
 10  select * from t1
 11  pivot XML (
 12    max(value)
 13    for rn in (ANY)
 14* )
SQL> /

NAM RN_XML
--- --------------------------------------------------------------------------------
Bob <PivotSet><item><column name = "RN">1</column><column name = "MAX(VALUE)">3</col
    umn></item><item><column name = "RN">2</column><column name = "MAX(VALUE)">4</co
    lumn></item></PivotSet>

Joe <PivotSet><item><column name = "RN">1</column><column name = "MAX(VALUE)">9</col
    umn></item></PivotSet>

Sam <PivotSet><item><column name = "RN">1</column><column name = "MAX(VALUE)">0</col
    umn></item><item><column name = "RN">2</column><column name = "MAX(VALUE)">1</co
    lumn></item></PivotSet>

详细了解pivot here

Oracle选择数据透视查询以使用通用列名将行放在其对应部分旁边

1 个答案: