Question

我有一个字符串，例如'“ F01” le code le“ F16”'我想解析该字符串以获取一个新字符串，其中包含“ F01”，“ F02，” F03“ ...直到” F16“。 / p>

我厌倦了用引号来解析字符串，希望循环遍历第一个代码直到最后一个代码。然后尝试通过chr（）和ord（）递增代码。但是似乎无法弄清楚。

import re
s = '"F01" le code le "F16"'

s_q = re.findall('"([^"]*)"', s)

first_code = s_q[0]
last_code = s_q[1]
ch_for_increment = s_q[0][-1:]
ch_for_the_rest = s_q[0][:-1]
print(ch_for_the_rest + chr(ord(ch) + 1))

Answer 1

您快到了。从s_q中提取范围的开始和结束之后，您可以像这样使用range来生成列表。

import re
s = '"F01" le code le "F16"'

s_q = re.findall('"([^"]*)"', s)
#['F01', 'F16']

#Extract the first and last index of range from list
first_code = int(s_q[0][1:])
#1
last_code = int(s_q[1][1:])
#16

#Create the result list
li = ['F{:02d}'.format(item) for item in range(first_code, last_code+1)]

#Get the final string with quotes
result = '"{}"'.format('" "'.join(li))

print(result)

输出将为

"F01" "F02" "F03" "F04" "F05" "F06" "F07" "F08" "F09" "F10" "F11" "F12" "F13" "F14" "F15" "F16"

如何在一定范围内增加字符串

1 个答案: