我在轮盘游戏中有一个固定的插槽数。从数字00到数字1(顺时针)开始。在我的Collection数组中,头寸计数为0到37。目前,我已经成功地将球的位置放在1度的数字中间。但是当我尝试传递数字位置时,我无法为每个位置计算正确的值。
我已经尝试弄乱计算结果了,它是球位于数字中间还是超出范围!
public class WheelDisplay extends JPanel implements ConstantVariable {
private Image image;
private ImageObserver imageObserver;
private float degrees = 1;
private int post = 0;
public WheelDisplay() {
ImageIcon icon = new ImageIcon(IMAGE_LOCATION);
image = icon.getImage();
imageObserver = icon.getImageObserver();
}
/** Credit to stackoverflow forum : https://stackoverflow.com/questions/25923480/simple-circle-rotation-simulate-motion **/
@Override
public void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
int circleDiameter = Math.min(getWidth(), getHeight());
double circleRadius = circleDiameter / 2;
int offSetX = (getWidth() - circleDiameter) / 2;
int offSetY = (getHeight() - circleDiameter) / 2;
g2d.drawImage(image, offSetX, offSetY, circleDiameter, circleDiameter, imageObserver);
g2d.setColor(Color.BLUE);
int ballDiameter = (int) (circleDiameter * 0.02);
int ballRadius = ballDiameter / 2;
Point p = getPointOnCircle(this.degrees, circleRadius * 0.9, circleRadius);
int valueX = offSetX + p.x - ballRadius;
int valueY = offSetY + p.y - ballRadius;
g2d.fillOval(valueX, valueY, ballDiameter, ballDiameter);
g2d.dispose();
}
private Point getPointOnCircle(float degress, double circleRadius, double innerCircleRadius) {
//The calculation that allow ball sit in the middle of each number when spin
double rads = ((Math.PI * degress) / 38);
// Calculate the outter point of the line
int xCordinate = Math.round((float) (innerCircleRadius + Math.cos(rads) * circleRadius));
int yCordinate = Math.round((float) (innerCircleRadius + Math.sin(rads) * circleRadius));
return new Point(xCordinate, yCordinate);
}
public void setDegree(int x) {
this.degrees += 2;
this.post = x; // The number of position coming from Collection (0-37)
}
}
球应该位于轮盘图像中每个38个数字的中间。
希望有人可以指出我做错了哪一部分!
我正在使用的图像是这个。