如何实现D3比例使孩子从毕业的父母那里继承色彩？

Question

我有一棵D3.js树，该树具有应用于节点和链接的不同颜色。

着色是硬编码的：

nodeUpdate.select("circle")
      .attr("r", 10)
       .style("fill", function(d) { 
     if(d.name == "Top Level") {
      return d._children ? "blue" : "#fff"; 
      }
    if(d.name == "Second A") {
     return d._children ? "red" : "#fff"; 
    }
      if(d.name == "Second B") {
      return d._children ? "green" : "#fff"; 
      }
    if(d.name == "Second C") {
      return d._children ? "purple" : "#fff"; 
      }
      if(d.name == "Second D") {
      return d._children ? "gold" : "#fff"; 
      }
    })
     .style("stroke", function(d) { 
     if(d.name == "Top Level") {
      return "blue"; 
      }
    if(d.name == "Second A") {
     return "red"; 
    }
      if(d.name == "Second B") {
      return "green"; 
      }
    if(d.name == "Second C") {
      return "purple"; 
      }
      if(d.name == "Second D") {
      return "gold"; 
      }
    });

和

link.enter().insert("path", "g")
      .attr("class", "link")
      .attr("stroke-width", function(d){
        return 1;
      })
      .attr("d", function(d) {
        var o = {x: source.x0, y: source.y0};
        return diagonal({source: o, target: o});
      })
    .style("stroke", function(d) {
      return linkColor(d.target.name);
    });

和

function linkColor(node_name) {
    switch (node_name)
    {
      case 'Second A': case 'Third A':  case 'Third B': 
        return 'red';
        break;
      case 'Second B': case 'Third C':  case 'Third D': 
        return 'green';
        break;
      case 'Second C': case 'Third E':  case 'Third F': 
        return 'purple';
        break;
      case 'Second D': case 'Third G':  case 'Third H': 
        return 'gold';
    }
}

请参见fiddle

我不是要对每个节点和链接的颜色进行硬编码，而是要实现d3-scale来为节点和线着色。该解决方案将使孩子沿着自动给定x个孩子数量的graduation of that colour“继承”其父母的颜色。

https://www.d3indepth.com/scales/

我该如何实现？

一如既往，感谢您的帮助。

Answer 1

您需要的刻度是序数刻度，如下所示：

var colourScale = d3.scale.ordinal()
    .domain(["Top Level","Second A", "Second B", "Second C", "Second D"])
    .range(["blue","red", "green", "purple", "gold"]);

然后，您可以更改整个内容...

.style("fill", function(d) {
    if (d.name == "Top Level") {
        return d._children ? "blue" : "#fff";
    }
    if (d.name == "Second A") {
        return d._children ? "red" : "#fff";
    }
    if (d.name == "Second B") {
        return d._children ? "green" : "#fff";
    }
    if (d.name == "Second C") {
        return d._children ? "purple" : "#fff";
    }
    if (d.name == "Second D") {
        return d._children ? "gold" : "#fff";
    }
})

...只是：

.style("fill", function(d) {
    return colourScale(d.name)
})

并摆脱该linkColor函数。

请注意，尽管您已经链接了D3 v5文档，但是您正在使用D3 v3。

这是您所做的更改的代码：

var treeData = [{
  "name": "Top Level",
  "children": [{
    "name": "Second A",
    "children": [{
      "name": "Third A"
    }, {
      "name": "Third B"
    }]
  }, {
    "name": "Second B",
    "children": [{
      "name": "Third C"
    }, {
      "name": "Third D"
    }]
  }, {
    "name": "Second C",
    "children": [{
      "name": "Third E"
    }, {
      "name": "Third F"
    }]
  }, {
    "name": "Second D",
    "children": [{
      "name": "Third G"
    }, {
      "name": "Third H"
    }, ]
  }, ]
}];

var colourScale = d3.scale.ordinal()
  .domain(["Top Level", "Second A", "Second B", "Second C", "Second D"])
  .range(["blue", "red", "green", "purple", "gold"]);


// ************** Generate the tree diagram	 *****************
var margin = {
    top: 20,
    right: 120,
    bottom: 20,
    left: 120
  },
  width = 960 - margin.right - margin.left,
  height = 500 - margin.top - margin.bottom;

var i = 0,
  duration = 750,
  root;

var tree = d3.layout.tree()
  .size([height, width]);

var diagonal = d3.svg.diagonal()
  .projection(function(d) {
    return [d.y, d.x];
  });

var svg = d3.select("body").append("svg")
  .attr("width", width + margin.right + margin.left)
  .attr("height", height + margin.top + margin.bottom)
  .append("g")
  .attr("transform", "translate(" + margin.left + "," + margin.top + ")");

root = treeData[0];
root.x0 = height / 2;
root.y0 = 0;

update(root);

d3.select(self.frameElement).style("height", "500px");


// Collapse after the second level
root.children.forEach(collapse);

update(root);

// Collapse the node and all it's children
function collapse(d) {
  if (d.children) {
    d._children = d.children
    d._children.forEach(collapse)
    d.children = null
  }
}

function update(source) {



  // Compute the new tree layout.
  var nodes = tree.nodes(root).reverse(),
    links = tree.links(nodes);

  // Normalize for fixed-depth.
  nodes.forEach(function(d) {
    d.y = d.depth * 180;
  });

  // Update the nodes…
  var node = svg.selectAll("g.node")
    .data(nodes, function(d) {
      return d.id || (d.id = ++i);
    });

  // Enter any new nodes at the parent's previous position.
  var nodeEnter = node.enter().append("g")
    .attr("class", "node")
    .attr("transform", function(d) {
      return "translate(" + source.y0 + "," + source.x0 + ")";
    })
    .on("click", click);

  nodeEnter.append("circle")
    .attr("r", 1e-6)
    .style("fill", function(d) {
      return d._children ? "#C0C0C0" : "#fff";
    });

  nodeEnter.append("text")
    .attr("x", function(d) {
      return d.children || d._children ? -13 : 13;
    })
    .attr("dy", ".35em")
    .attr("text-anchor", function(d) {
      return d.children || d._children ? "end" : "start";
    })
    .text(function(d) {
      return d.name;
    })
    .style("fill-opacity", 1e-6);

  // Transition nodes to their new position.
  var nodeUpdate = node.transition()
    .duration(duration)
    .attr("transform", function(d) {
      return "translate(" + d.y + "," + d.x + ")";
    });

  nodeUpdate.select("circle")
    .attr("r", 10)
    .style("fill", function(d) {
      return d.depth === 2 ? colourScale(d.parent.name) : colourScale(d.name);
    })
    .style("stroke", function(d) {
      return d.depth === 2 ? colourScale(d.parent.name) : colourScale(d.name);
    });

  nodeUpdate.select("text")
    .style("fill-opacity", 1);

  // Transition exiting nodes to the parent's new position.
  var nodeExit = node.exit().transition()
    .duration(duration)
    .attr("transform", function(d) {
      return "translate(" + source.y + "," + source.x + ")";
    })
    .remove();

  nodeExit.select("circle")
    .attr("r", 1e-6);

  nodeExit.select("text")
    .style("fill-opacity", 1e-6);

  // Update the links…
  var link = svg.selectAll("path.link")
    .data(links, function(d) {
      return d.target.id;
    });

  // Enter any new links at the parent's previous position.
  link.enter().insert("path", "g")
    .attr("class", "link")
    .attr("stroke-width", function(d) {
      return 1;
    })
    .attr("d", function(d) {
      var o = {
        x: source.x0,
        y: source.y0
      };
      return diagonal({
        source: o,
        target: o
      });
    })
    .style("stroke", function(d) {
      return d.target.depth === 2 ? colourScale(d.target.parent.name) : colourScale(d.target.name);
    });

  // Transition links to their new position.
  link.transition()
    .duration(duration)
    .attr("d", diagonal);

  // Transition exiting nodes to the parent's new position.
  link.exit().transition()
    .duration(duration)
    .attr("d", function(d) {
      var o = {
        x: source.x,
        y: source.y
      };
      return diagonal({
        source: o,
        target: o
      });
    })
    .remove();

  // Stash the old positions for transition.
  nodes.forEach(function(d) {
    d.x0 = d.x;
    d.y0 = d.y;
  });
}


// Toggle children on click.
function click(d) {
  if (d.children) {
    d._children = d.children;
    d.children = null;
  } else {
    d.children = d._children;
    d._children = null;
  }
  update(d);
}

.node {
  cursor: pointer;
}

.node circle {
  fill: #fff;
  stroke: #C0C0C0;
  stroke-width: 1.5px;
}

.node text {
  font: 10px sans-serif;
}

.link {
  fill: none;
  stroke: #C0C0C0;
  stroke-width: 1.5px;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.5.17/d3.min.js"></script>