我有一个XML。我已经将其转换为类文件,因此可以将值传递到该节点的xml对象中。但是我坚持要传递下面这个对象的值。您能描述一下我该如何编写相同的代码。最后一个问题是我提供了我的代码
<m:SaveOrder xmlns:m = 'http://www.e-courier.com/schemas/' >
下面是xml
<SOAP:Envelope xmlns:SOAP='http://schemas.xmlsoap.org/soap/envelope/' >
<SOAP:Body UserGUID = '{redacted}' >
<m:SaveOrder xmlns:m = 'http://www.e-courier.com/schemas/' >
<Order UserID = '1' Notes = 'Pick CVS Lenexa.' CustomerID = '3' >
</Order >
</m:SaveOrder >
</SOAP:Body >
</SOAP:Envelope>
下面是为xml创建的类。
[XmlRoot(ElementName="Order")]
public class Order {
[XmlAttribute(AttributeName="UserID")]
public string UserID { get; set; }
[XmlAttribute(AttributeName="Notes")]
public string Notes { get; set; }
[XmlAttribute(AttributeName="CustomerID")]
public string CustomerID { get; set; }
}
[XmlRoot(ElementName="SaveOrder", Namespace="http://www.e-courier.com/schemas/")]
public class SaveOrder {
[XmlElement(ElementName="Order")]
public Order Order { get; set; }
[XmlAttribute(AttributeName="m", Namespace="http://www.w3.org/2000/xmlns/")]
public string M { get; set; }
}
[XmlRoot(ElementName="Body", Namespace="http://schemas.xmlsoap.org/soap/envelope/")]
public class Body {
[XmlElement(ElementName="SaveOrder", Namespace="http://www.e-courier.com/schemas/")]
public SaveOrder SaveOrder { get; set; }
[XmlAttribute(AttributeName="UserGUID")]
public string UserGUID { get; set; }
}
[XmlRoot(ElementName="Envelope", Namespace="http://schemas.xmlsoap.org/soap/envelope/")]
public class Envelope {
[XmlElement(ElementName="Body", Namespace="http://schemas.xmlsoap.org/soap/envelope/")]
public Body Body { get; set; }
[XmlAttribute(AttributeName="SOAP", Namespace="http://www.w3.org/2000/xmlns/")]
public string SOAP { get; set; }
}
我卡住的代码
var SaveOrder = new ECSaveOrderRequest.Envelope
{
Body = new ECSaveOrderRequest.Body
{
UserGUID = guid,
SaveOrder = new ECSaveOrderRequest.SaveOrder
{
}
}
};