昨天我在Assembly中发布了一个关于我的Recursive Fibonacci程序的问题。我现在得到了正确的输出,感谢这里精彩人士的一些帮助,但是在打印出正确的输出之后,我的程序崩溃了。
以下是调用Fibonacci程序给定次数的Sequence程序(存储在L中)
.386
.model Flat
public Sequence
extrn Fibonacci:proc
include iosmacros.inc
.code
Sequence proc
MOV L, EAX
XOR ECX, ECX ;start count at 0
sequ:
CMP ECX, L
JA endseq ;if we have passed the given value (L), end
putstr MsgOut1
putint ECX ;number passed to Fibonacci
putstr MsgOut2
MOV count, ECX ;preserve count
PUSH ECX
CALL Fibonacci ;call Fibonacci
putint ECX
putch ' '
MOV ECX, count ;restore count
INC ECX ;increment the count
JMP sequ ;again
endseq:
putint ecx
ret
Sequence endp
.data
MsgOut1 DB "Fib(", 0, 0 ;first half of output message
MsgOut2 DB ") = ", 0, 0 ;second half of output message
L DD, 0, 0 ;number of sequences to carry out
count DD 0,0 ;for counting
end
以下是调用Sequence过程的代码:
.386
.model flat
extrn Sequence:proc
include Cs266.inc
.data
Msg DB "Please input the number of sequences you would like carried out", 0Ah, 0 ;input request message
err DB "reached end"
.code
include Rint.inc
main:
putstr Msg
CALL Rint ;store int in EAX
CALL Sequence
putstr err
ret
end
Fibonacci代码如下:
.386
.model Flat
public Fibonacci
include iosmacros.inc ;includes macros for outputting to the screen
.code
Fibonacci proc
MOV ECX, [ESP+4]
CMP ECX, 1
JA Recurse
MOV ECX, 1 ;return value in ECX
JMP exit
Recurse:
PUSH EBX ;preserve value of EBX
DEC ECX
PUSH ECX
CALL Fibonacci
MOV EBX, ECX ;EBX is preserved, so safe to use
DEC [ESP] ;decrement the value already on the stack
CALL Fibonacci
ADD ECX, EBX ;return value in ECX
ADD ESP, 4 ;remove value from stack
POP EBX ;restore old value of EBX
exit:
ret
Fibonacci endp
.data
end
我在这里发布了一堆代码,但这只是为了方便我指出正确的方向。我相信问题可能在序列中,而我的调试器对我没有帮助。
编辑:我得到的所有错误都是这样的: http://imgur.com/XulTl 如果我确实启用了Visual Studio实时调试,那么它永远不会有帮助。
答案 0 :(得分:1)
嗯...在Fibonacci
中,我看到两个push
es,只有一个pop
。至少乍一看,这似乎有点问题。