python字母和数字中的两个列表的笛卡尔积

Question

当前

list1 = ['A','B','C']
list2 = [1,2,3]

所需

list 3 = [['A', 1], ['A', 2], ['A', 3], ['B', 1], ['B', 2],['B', 3],
 ['C', 1], ['C', 2], ['C', 3]]

我尝试过的

list3 = [l+str(n) for l in list1 for n in list2]

导致：

['A1', 'A2', 'A3', 'B1', 'B2', 'B3', 'C1', 'C2', 'C3']

Answer 1

您很亲密：

[[l,n] for l in list1 for n in list2]

Answer 2

[[l]+[n] for l in list1 for n in list2]

Answer 3

正如Mark所提到的，itertools.product将是必经之路。但是，如果您想继续使用列表理解功能，则正确的行应该是

list3 = [ [l, str(n)] for l in list1 for n in list2 ]