Question

我正在使用熊猫读取多个文件，并且需要使用原始的filename_corrected保存每个文件。如何使用原始文件名+前缀或数字来重命名输出文件？

import pandas as pd
import glob
import os

#Read all files in using pandas
path = r'J:\Temp\\' 
all_files = glob.glob(path + "/*.97o")

for filename in all_files:
   df = pd.read_csv (filename)
   df = df.replace(to_replace ='1997     7    23 ', value = '2019     5    23 ', regex = True)
   df = df.replace(to_replace ='97  7 23', value = '19  5 23', regex = True)
   df.to_csv('J:\Temp\94512040_corrected.97o', index=False)

输出文件应名为：filename_corrected.97o

Answer 1

您可以使用基于旧名称的格式字符串来创建新文件名：

import pandas as pd
import glob
import os

#Read all files in using pandas
path = r'J:\Temp\\' 
all_files = glob.glob(path + "/*.97o")

for filename in all_files:

   df = pd.read_csv(filename)
   df = df.replace(to_replace ='1997     7    23 ', value = '2019     5    23 ', regex = True)
   df = df.replace(to_replace ='97  7 23', value = '19  5 23', regex = True)
   fileBaseName = os.path.basename(filename).split('.')[0]
   newFilename = '{}{}_corrected.97o'.format(path, fileBaseName)
   df.to_csv(newFilename, index=False)

Python熊猫使用不同的名称保存多个CSV

1 个答案: