Question

所以我想在keras之后计算R2 = 1 - residual_ss/y_ss。我使用预测model.predict()来计算residual_ss。但是，residual_ss比y_ss大得多，这导致负R2。由于residual_ss = n*mse和mse也是损失函数，因此代码在模型之后显示了mse的计算结果：


import keras
keras.__version__
from keras.datasets import boston_housing
import pandas as pd
import numpy as np

(train_data, train_targets), (test_data, test_targets) =  boston_housing.load_data()
mean = train_data.mean(axis=0)
train_data -= mean
std = train_data.std(axis=0)
train_data /= std

test_data -= mean
test_data /= std

from keras import models
from keras import layers

def build_model():
    # Because we will need to instantiate
    # the same model multiple times,
    # we use a function to construct it.
    model = models.Sequential()
    model.add(layers.Dense(64, activation='relu',
                           input_shape=(train_data.shape[1],)))
    model.add(layers.Dense(64, activation='relu'))
    model.add(layers.Dense(1))
    model.compile(optimizer='rmsprop', loss='mse', metrics=['mae'])
    return model

model=build_model()
model.fit(train_data,  train_targets, epochs=200, batch_size=32)

#try to get mse
y_pred = model.predict(train_data)
mse=np.mean((train_targets-y_pred)*(train_targets-y_pred))
print(mse)

这是最后3个纪元，mse最后是

Epoch 198/200
404/404 [=======] - 0s 17us/step - loss: 3.4695 - mean_absolute_error: 1.3338
Epoch 199/200
404/404 [=======] - 0s 22us/step - loss: 3.5412 - mean_absolute_error: 1.3260
Epoch 200/200
404/404 [=======] - 0s 20us/step - loss: 3.2775 - mean_absolute_error: 1.2858
162.25934358457062

我在这里仅使用train_data和train_targets。为什么我得到的mse甚至不接近每个时期报告的损失（mse）？因此，预测距离目标还很近。请帮忙。

在keras模型之后计算ms。预测似乎是错误的

0 个答案: