Question

我正在尝试使用Python 2.7.15中的乌龟制作一款类似于Atari 2600冒险游戏的游戏。我能做到使乌龟不能越过乌龟画出的线吗？

我需要我的乌龟在检测到某种颜色时执行某些操作，例如当它撞到蓝色时无法穿越绿色或打开门。如果您能帮助我弄清楚在乌龟碰到乌龟后如何让收藏品（钥匙）跟随乌龟，则可获得加分。这是我的代码：

from turtle import *
import turtle as t

color = raw_input("Enter an avatar color in the form of a hex code (Black won't show because the background is black): ")
c = Turtle()
loop = 0

def bdr():
    c.color(color)
    c.up()
    c.goto(0,-185)
    c.seth(90)
    t.ht()
    t.bgcolor("#000000")
    t.color("#00ff00")
    t.speed(0)
    t.up()
    t.rt(90)
    t.fd(200)
    t.rt(90)
    t.fd(200)
    t.rt(180)
    t.down()
    for box in range (4):
        t.fd(400)
        t.lt(90)
    t.up()
    t.fd(200)

def k1():
    c.seth(90)
    c.fd(5)

def k2():
    c.seth(180)
    c.fd(5)

def k3():
    c.seth(0)
    c.fd(5)

def k4():
    c.seth(270)
    c.fd(5)

bdr()

onkey(k1, "Up")
onkey(k2, "Left")
onkey(k3, "Right")
onkey(k4, "Down")

listen()
mainloop()

我不尝试任何颜色检测，因为我不知道从哪里开始。

Answer 1

我建议您不基于颜色进行碰撞检测。您有可能跌倒乌龟的tkinter基础，但是由于乌龟正在盒子内移动，因此测试坐标要简单得多：

from turtle import Screen, Turtle, mainloop

SIZE = 400
DISTANCE = 5
CURSOR_SIZE = 20

def draw_border():

    border = Turtle(visible=False)
    border.color("green")
    border.speed('fastest')

    border.penup()
    border.goto(-SIZE/2, -SIZE/2)
    border.pendown()

    for _ in range(4):
        border.forward(SIZE)
        border.lt(90)

def k1():
    player.setheading(90)

    if player.ycor() + DISTANCE < SIZE/2:
        player.forward(DISTANCE)

def k2():
    player.setheading(180)

    if player.xcor() - DISTANCE > -SIZE/2:
        player.forward(DISTANCE)

def k3():
    player.setheading(0)

    if player.xcor() + DISTANCE < SIZE/2:
        player.forward(DISTANCE)

def k4():
    player.setheading(270)

    if player.ycor() - DISTANCE > -SIZE/2:
        player.forward(DISTANCE)

color = raw_input("Enter avatar color as a hex code (black won't show): ")

screen = Screen()
screen.bgcolor("black")

player = Turtle(visible=False)
player.speed('fastest')
player.color(color)
player.up()
player.sety(CURSOR_SIZE/2 - SIZE/2)
player.setheading(90)
player.showturtle()

draw_border()

screen.onkey(k1, "Up")
screen.onkey(k2, "Left")
screen.onkey(k3, "Right")
screen.onkey(k4, "Down")

screen.listen()
mainloop()

就门和钥匙而言，如果您也将它们做成乌龟，则只需使用乌龟的.distance()方法即可进行碰撞检测。

使其不会龟越过龟线

1 个答案: