Question

我有一个测试，其中我必须对服务器进行REST调用，只有接到该电话后，我才能继续进行其余的测试，我不能使用sleep(x)，因为它将阻塞主线程，并且不会让其余的调用完成。

这是一个代码示例，可以更好地解释：

let homeInteractor: HomeInteractor = HomeInteractor ()
homeInteractor.initSDK()

//// <<<<< DO A DELEY HERE FOR 5 SECONDS
//sleep(5) < CANNOT USE SLEEP AS IT WILL BLOCK THE MAIN THREAD

let loginInteractor: LoginInteractor = LoginInteractor ()
let loginViewController: LoginTableViewController = LoginTableViewController ()
let loginPresenter: LoginPresenter = LoginPresenter(controller: loginViewController)

loginPresenter.onLoginButtonPressed(usernameText: "username", passwordText: "password")

waitForExpectations(timeout: 10)

 XCTAssertEqual(loginPresenter.didUserLogin, true)

如何实现这种延迟？

Answer 1

尝试一下：

// The code you didn't know when will finish
let homeInteractor: HomeInteractor = HomeInteractor ()
homeInteractor.initSDK()

// The time you guess it needs
let delay: TimeInterval = 5
let expectation = XCTestExpectation()

// Rest of the code after that delay
DispatchQueue.main.asyncAfter(deadline: .now() + delay) {

    let loginInteractor: LoginInteractor = LoginInteractor ()
    let loginViewController: LoginTableViewController = LoginTableViewController ()
    let loginPresenter: LoginPresenter = LoginPresenter(controller: loginViewController)

    loginPresenter.onLoginButtonPressed(usernameText: "username", passwordText: "password")

    // fulfil expectations
    XCTAssertEqual(loginPresenter.didUserLogin, true)
    if loginPresenter.didUserLogin {
        expectation.fulfill()
    }
}

// Wait for it
wait(for: [expectation], timeout: delay)

如何在不阻塞主线程的情况下以Xcode为单位执行延迟？

1 个答案: