我必须完成目前正在做的工作,并且要进行一些更改,因此我坚持希望在提交之前遇到的最后一个问题
我需要为电影院创建一个简单的票务系统,并且已经能够(在其他经验丰富的开发人员的帮助下)创建一个工作系统。但是,票务系统需要提示用户进行确认以继续该方法,并显示当前的总费用。确认必须是用户输入数字1(如果没有输入),以输出错误消息。
我尝试使用again = br.readLine();
输出1以确认购买,我还尝试导入java.util.Scanner
类,然后输入并使用int
创建错误消息但它继续显示错误。
package ticketingsystem;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class ticketingsystem {
enum TicketType {
// I chose to use the enum class for the ticket prices, //
// as it made it much easier to use a switch statement, instead of multiple if statements. //
CHILD(18), ADULT(36), SENIOR(32.5);
//Enum classes are needed to be used in upper case, otherwise the program will crash//
//as I discovered//
TicketType(double price) {
this.price = price;
}
private double price;
public double getPrice() {
return price;
}
}
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
//As the program needed the ability to run in an indefinite loop constantly adding //
//calculations, I chose to use buffered reader, as it buffered the method each loop//
//continuing to add a total number.//
String type, again;
int quantity = 0;
// This is where the new calculation starts, it is set at 0 before being calculated and
//added to the total price.//
double totalPrice = 0;
TicketType ticketType;
//We link the TicketType calculations to the enum class, hence//
// TicketType ticketType.//
System.out.println("Welcome to the cinemas!");
System.out.println("MAIN MENU\n");
System.out.println("Cinema has the following ticketing options\n");
System.out.println("1 = Child (4-5 yrs)");
System.out.println("2 = Adult (18+ yrs)");
System.out.println("3 = Senior (60+ yrs)");
do {
//Our loop calculation method starts here//
System.out.print("\nEnter your option: ");
type = br.readLine();
switch (type.toLowerCase()) {
case "1":
ticketType = TicketType.CHILD;
break;
case "2":
ticketType = TicketType.ADULT;
break;
default:
ticketType = TicketType.SENIOR;
break;
}
System.out.print("Enter total No of tickets: ");
quantity = Integer.parseInt(br.readLine());
totalPrice += ticketType.getPrice() * quantity;
//totalPrice is the ticketType cost (hence the += operator), times//
//the quantity.//
System.out.printf("--> You are purchasing %s - %s Ticket(s) at $%s\n", quantity, ticketType, ticketType.getPrice());
System.out.println("Press 1 to confirm purchase");
//This is where we confirm the purchase//
// This is where the current total cost needs to be output //
System.out.print("\nDo you wish to continue? (Y/N) : ");
again = br.readLine();
} while (again.equalsIgnoreCase("y"));
//This is where the calculation method ends (as we are using a do/while loop).//
// The while statement means that if we type "y", the loop will begin again with a buffer.//
//If we type N, the loop will end, and the program will continue running past the loop.//
System.out.printf("\n==> Total Price : $%s \n", totalPrice);
}
}
答案 0 :(得分:1)
如果您希望用户必须按1
来接受购买,则在问完该问题后只需输入一个简单的if...else
即可。像这样:
String confirmation = br.readLine();
if (confirmation.equals("1")) {
totalPrice += ticketType.getPrice() * quantity;
System.out.println("Current total is: " + totalPrice);
} else {
System.out.println("You did not press 1 so ticket purchase cancelled");
System.out.println("Current cost is still: " + totalPrice);
}
因此,只有当他们按下1
时,它才会更新总数。