我有一个名为Test的表,具有以下值
ID Name Description
1 Xyz Mumbai,Delhi
我想要Sql查询,它将给出如下输出
ID Name Description
1 Xyz Mumbai
1 Xyz Delhi
答案 0 :(得分:0)
您可以将regexp_substr
与'[^,]+'
模式一起用作第二个参数,以分隔逗号分隔的字符串
with tab( ID, Name, Description ) as
(
select 1,'Xyz','Mumbai,Delhi' from dual
)
select ID, Name,
regexp_substr(Description,'[^,]+',1,level)
as Description
from tab
connect by level <= regexp_count(Description,',')+1;
ID NAME DESCRIPTION
-- ---- -----------
1 Xyz Mumbai
1 Xyz Delhi