该程序的目的是获取偶数个用户输入的整数并对它们进行排序（使用合并排序）。它将排序列表打印到屏幕上。程序首先获取设置大小，然后询问整数。它将它们分成两个甚至是单独的集合，然后从这里按升序对它们进行排序。当两个集合都已排序时，程序将在最终排序集合中将两个集合合并在一起。然后将最终设置打印到屏幕上。 我得到的输出只是一个0的列表。不确定我的错误在哪里，可以使用一些新鲜的眼睛。感谢。
.data
msg1:
.asciiz "Please Enter the the total even number of integers in the list: "
.align 2
msg2:
.asciiz "\nPlease Enter an integer: "
.align 2
msg3:
.asciiz "\nSorted list of integers is: "
.align 2
coma:
.asciiz ", "
.align 2
set1:
.space 69
.align 2
set2:
.space 69
.align 2
set3:
.space 138
.align 2
.text
.globl main
main:
#Get input for size of sortedSet, divide it in half to get size of two
#final sorted sets to merge and store them into arguements
li $v0, 4
la $a0, msg1 #prints message1 to screen
syscall
li $v0, 5
syscall #inputed value is number of elements
move $s3, $v0
beqz $s3, main #check if inputed value is greater than zero
li $t2, 2
div $s3, $t2 #divides size of final array by 2
mflo $s4 #stores quotient as size of smaller arrays
Enter:
#Get input of each integer in the list, after each entered integer itterator is increased by 1.
#input will be saved into set1,when size is equal set1size input will be saved into set2.
beq $t4, $s4, Enter2 #branch to set2 when set1 is full
li $v0, 4
la $a0, msg2
syscall #print message2 to screen, taking input for set1
li $v0, 5
syscall #takes inputed user value
move $a1, $v0
la $a0, set1
move $t2, $t4
sll $t2, $t2, 2 #times itterator by 4
add $t1, $t2, $a0
sw $a1, ($t1) #stores user value as current element of set1
addi $t4, $t4, 1 #$t4 is itterator for entering loop. Increase by 1 to move to next space in set1
j Enter
Enter2:
beq $t5, $s4, step #branch to step after both sets are full
li $v0, 4
la $a0, msg2
syscall #print message2 to screen, taking input for set2
li $v0, 5
syscall #takes inputed user value
move $a1, $v0
la $a0, set2
move $t2, $t5
sll $t2, $t2, 2 #times itterator by 4
add $t1, $t2, $a0
sw $a1, ($t1) #stores user value as current element of set2
addi $t5, $t5, 1 #$t5 is itterator for second entering loop. Increase by 1 to move to next spot in set2
j Enter2
step:
#resets itterators for safety/to use again
li $t4, 0
li $t5, 0
sort:
#sort each individual list to create two sorted list in ascending order for the final
# merge-sort with two lists.
#first set
beq $t4, $s4, next #branch to next (second set) when itterator is equal to size of set1
la $a0, set1
move $t2, $t4 #move current spot into $t2 to preserve itterator
sll $t2, $t2, 2 # times by 4
add $t1, $t2, $a0 #get address of first element
lw $s1, ($t1) #load first element into $s1
move $t2, $t4
addi $t2, $t2, 1 #add 1 to itterator to get next element in set
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s2, ($t1) #load next element in set to $s2
bge $s1, $s2, switch #if set1[$s1] >= set1[$s2] goto label switch
addi $t4, $t4, 1 #add 1 to itterator
j sort
switch:
la $a0, set1 #switch set1[$s1] and set1[$s1+1]
move $t2, $t4
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s2, ($t1) #store $s2 into the $s1 spot
move $t2, $t4
addi $t2, $t2, 1
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s1, ($t1) #store $s1 into the $s2 spot
addi $t4, $t4, 1 #add 1 to itterator
j sort
next:
beq $t5, $s4, merge #branch to merge when itterator equals set2 size
la $a0, set2 #load address of set2
move $t2, $t5 #move itterator to $t2 to preserve it
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s1, ($t1) #load element into $s1
move $t2, $t5
addi $t2, $t2, 1 #add 1 to itterator for next element
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s2, ($t1) #load next element into $s2
bge $s1, $s2, switch2 #if set2[$t5] >= set2[$t5+1] goto label switch2
addi $t5, $t5, 1 #add 1 to itterator
j next
switch2:
la $a0, set2 #switch set2[$s2] and set2[$s2+1]
move $t2, $t5
addi $t2, $t2, 1
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s1, ($t1) #store $s1 into $s2 spot
move $t2, $t5
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s2, ($t1) #store $s2 into $s1 spot
addi $t5, $t5, 1 #add 1 to itterator
j next
merge:
#resets itterators for safety/to use again
li $t4, 0 # = set1 itterator
li $t5, 0 # = set2 itterator
li $t7, 0 # = set3 itterator
while:
#while($s1 <= $s4 || $s2 <= $s4) do{
# if($s1 == $s4){ set3[$s3] = set2[$s2]; addi $s2, 1; addi $s3, 1;
# j while}
# if($s2 == $s4){ set3[$s3] = set1[$s1]; addi $s1, 1; addi $s3, 1;
# j while}
# if(set1[$s1] > set2[$s2]){ set3[$s3] = set1[$s1]; addi $s1, 1;}
# else{ set3[$s3] = set2[$s2]; addi $s2, 1;}
# addi $s3, 1;
#} return
# break
beq $t4, $s4, print #1st part of while conditional, branch to print if $t4 = $s4
here:
beq $t4, $s4, if1 #1st if statement, branch to if1 loop if $t4 = $s4
beq $t5, $s4, if2 #2nd if statement, branch to if2 loop if %t5 = $s4
la $a0, set1 #3rd if statement
move $t2, $t4
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s1, ($t1) #load first element from set1 into $s1
la $a0, set2
move $t2, $t5
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s2, ($t1) #load first element from set2 into $s2
slt $t6, $s2, $s1 #returns 1 if $s1 > $s2
bnez $t6, if3 #if $t6 =/= 0, branch to if3 loop
beqz $t6, else3 #if $t6 = 0, branch to else3 loop
if1:
#branch for $s1 == $s4
# set3[$t7] = set2[$t4];
la $a0, set2 #load set2 address
move $t2, $t4
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s1, ($t1) #load element at $t4 in set2 to $s1
la $a0, set3 #load set3
move $t2, $t7
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s1, ($t1) #store $s1 into $t7 position in set3
addi $t4, $t4, 1 #add 1 to $t4 itterator
addi $t7, $t7, 1 #add 1 to $t7 itterator
j while
if2:
#branch for $s2 == $s4
# set3[$t7] = set1[$t4];
la $a0, set1 #load set1 address
move $t2, $t4 #load itterator into $t2
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s1, ($t1) #load element in position $t4 into $s1
la $a0, set3 #load set3 address
move $t2, $t7
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s1, ($t1) #store $s1 into position $t7 in set3
addi $t4, $t4, 1 #move to next position in set1
addi $t7, $t7, 1 #move to next position in set3
j while
if3:
#branch for set1[$t4] > set2[$s2]
# set3[$t7] = set1[$t4];
la $a0, set1 #load set1 address
move $t2, $t4 #move set1 itterator
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s1, ($t1) #load element at $t4 of set1 into $s1
la $a0, set3 #load set3 address
move $t2, $t7 #load set3 itterator
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s1, ($t1) #store $s1 into set3 at position $t7
addi $t4, $t4, 1 #move to next position in set1
addi $t7, $t7, 1 #move to next position in set3
j while
else3:
#branch for set1[$s1] < set2[$t5]
# set3[$t7] = set2[$t5];
la $a0, set2 #load set2 address
move $t2, $t5 #move set2 itterator to $t2
sll $t2, $t2, 2
add $t1, $t2, $a0
lw $s2, ($t1) #load element in position $t5 of set2 into $s2
la $a0, set3 #load set3 address
move $t2, $t7 #move set3 itterator
sll $t2, $t2, 2
add $t1, $t2, $a0
sw $s2, ($t1) #store element $s2 into position $t7 in set3
addi $t5, $t5, 1 #move to next position in set2
addi $t7, $t7, 1 #move to next position in set3
j while
print:
#itterate through sortedSet and print it to console then exit
blt $t5, $s4, here #go to label here if 2nd part of while conditional is not met
li $v0, 4
la $a0, msg3 #load msg3
syscall #print to screen
la $t3, set3 #load addresss of set3
move $t2, $s3 #move set3 size into $t2
li $t7, 0 #load 0 into set3 itterator
print2:
sll $t7, $t7, 2
add $t1, $t7, $t3
li $v0, 1
lw $a0, ($t3) #load element at position $t2 of set3 into $a0
syscall #print to screen
li $v0, 4
la $a0, coma #load address of coma
syscall #print screen
addi $t7, $t7, 1 #move to next element in set3
addi $t2, $t2, -1 #subtract 1 from set3 size
bnez $t2, print2 #if set3 size =/= 0, branch to print2
li $v0, 10
syscall #exit program
答案 0 :(得分：0)
嘿，我的代码遇到了同样的问题，但我想出来了，在我打印之前，地雷与我加载数组间距地址有关。我看到你再次加载set3但问题可能是你实际存储寄存器中的值或加载正确的寄存器